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我正在使用 GCM（Google Cloud Messaging）向 Android 应用发送通知。我的服务器使用的是 Google 提供的gcm-server.jar，我正在关注文档。我能够毫无问题地向设备发送通知。

现在我正在尝试根据从私有方法返回的Result(源) 对业务逻辑进行单元测试。PushNotificationDaoGcmImplsendNotificationToServer

我知道由于它是一个类Result而不能被模拟，并且由于没有公共构造函数而简单地将其实例化是行不通的。内部类在外部无法访问，因此我无法以这种方式构建对象。 finalnew Result()ResultBuilderpackage com.google.android.gcm.server;

我没有找到一个好方法来创建一个Result从Sender( source ) 返回的内容。

我的问题是我将如何进行PushNotificationDaoGcmImpl基于 处理某些条件的单元测试Result？

public class PushNotificationDaoGcmImpl{

    //method I'm trying to test
    public void sendPushNotification(){
        // builds message to send

        Result result = this.sendNotificationToServer(gcmMessage, deviceToken)

        //handle result's error conditions
    }

    //method call I'm trying to mock
    private Result sendNotificationToServer(Message gcmMessage, String deviceToken){
        return gcmSender.send(gcmMessage, deviceToken, 1);
    }
}   

//test snipet
@Test
public void testSendNotificationToServer () throws Exception {
    Result result = new Result();

    PushNotificationMessage message = new PushNotificationMessage("123", "Test", "deviceToken", "Android");

    //Having issue with how to handle Result here
    doReturn(result).when(gcmPushNotificationDaoSpy).sendNotificationToServer(any(Message.class), anyString());

    PushNotificationResult result = gcmPushNotificationDaoSpy.sendPushNotification(message);

    //verify business logic was correct based on Result
}
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2 回答 2

2

您还可以在 com.google.android.gcm.server 包中创建一个 MockResult 类，它可以让您访问 Builder。

package com.google.android.gcm.server;

class MockResult {

    public static Result mockResult(...) {
      // Use Builder here to construct Result
    }

}

对我来说，这感觉比处理反射更容易管理。

于 2012-12-31T02:27:14.183 回答
2

我想到的解决方案是使用反射来创建Result对象。我不确定这是否是一种好方法，但我能够根据不同的Result错误代码测试业务逻辑。

@Test
public void testSendNotificationToServer () throws Exception {
    String successIndicator = null;
    Result result = buildFauxResult("messageId", "deviceToken", successIndicator);

    PushNotificationMessage message = new PushNotificationMessage("123", "Test", "deviceToken", "Android");

    //Having issue with how to handle Result here
    doReturn(result).when(gcmPushNotificationDaoSpy).sendNotificationToServer(any(Message.class), anyString());

    PushNotificationResult result = gcmPushNotificationDaoSpy.sendPushNotification(message);

    //verify business logic was correct based on Result
}

public Result buildFauxResult (String messageId, String canonicalRegistrationId, String errorCode) throws Exception {
           Class <?> builderClass = Class.forName("com.google.android.gcm.server.Result$Builder");
           Constructor <?> builderConstructor = builderClass.getDeclaredConstructors()[0];
           ReflectionUtils.makeAccessible(builderConstructor);
           Object builderObject = builderConstructor.newInstance();

           Method canonicalRegistrationIdMethod = builderClass.getMethod("canonicalRegistrationId", String.class);
           ReflectionUtils.makeAccessible(canonicalRegistrationIdMethod);
           builderObject = ReflectionUtils.invokeMethod(canonicalRegistrationIdMethod, builderObject, canonicalRegistrationId);

           Method messageIdMethod = builderClass.getMethod("messageId", String.class);
           ReflectionUtils.makeAccessible(messageIdMethod);
           builderObject = ReflectionUtils.invokeMethod(messageIdMethod, builderObject, messageId);

           Method errorCodeMethod = builderClass.getMethod("errorCode", String.class);
           ReflectionUtils.makeAccessible(errorCodeMethod);
           builderObject = ReflectionUtils.invokeMethod(errorCodeMethod, builderObject, errorCode);

           Method buildMethod = builderClass.getMethod("build");
           ReflectionUtils.makeAccessible(buildMethod);

           return (Result) ReflectionUtils.invokeMethod(buildMethod, builderObject);
    }
于 2012-12-05T21:40:31.657 回答