6

我将如何在下面的这种方法中捕获异常？

    private static Task<string> MakeAsyncRequest(string url)
    {
        if (!url.Contains("http"))
            url = "http://" + url;

        HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
        request.UserAgent = "Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1; .NET CLR 1.1.4322; .NET CLR 2.0.50727)";
        request.Accept = "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8";
        request.Method = "GET";
        request.KeepAlive = false;
        request.ProtocolVersion = HttpVersion.Version10;

        Task<WebResponse> task = Task.Factory.FromAsync(
        request.BeginGetResponse,
        asyncResult => request.EndGetResponse(asyncResult),
        (object)null);

        return task.ContinueWith(t => FinishWebRequest(t.Result));

    }

我得到 404、403 等错误的具体地方是：

Task<WebResponse> task = Task.Factory.FromAsync(
            request.BeginGetResponse,
            asyncResult => request.EndGetResponse(asyncResult),
            (object)null);

我不知道如何处理它们

4

2 回答 2

13

您的错误可能发生在您的委托调用request.EndGetResponse(asyncResult)中。

但是，您可以使用以下方法创建任务：

Task<WebResponse> task = Task.Factory.FromAsync<WebResponse>(request.BeginGetResponse, request.EndGetResponse, null);

这应该将任何异常传播到任务。

您可以检查ContinueWith委托中的错误：

return task.ContinueWith(t =>
{
    if (t.IsFaulted)
    {
        //handle error
        Exception firstException = t.Exception.InnerExceptions.First();
    }
    else
    {
        return FinishWebRequest(t.Result);
    }
});

或者，如果您使用 C#5，那么您可以使用 async/await 创建您的MakeAsyncRequest. 这将为AggregateException您解开异常：

private static async Task<string> MakeAsyncRequest(string url)
{
    if (!url.Contains("http"))
        url = "http://" + url;

    HttpWebRequest request = (HttpWebRequest)WebRequest.Create(url);
    request.UserAgent = "Mozilla/4.0 (compatible; MSIE 7.0; Windows NT 5.1; .NET CLR 1.1.4322; .NET CLR 2.0.50727)";
    request.Accept = "text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8";
    request.Method = "GET";
    request.KeepAlive = false;
    request.ProtocolVersion = HttpVersion.Version10;

    Task<WebResponse> task = Task.Factory.FromAsync<WebResponse>(request.BeginGetResponse, request.EndGetResponse, null);
    WebResponse response = await task;
    return FinishWebRequest(response);
}
于 2012-12-03T18:47:52.003 回答
1

因此，您的任务将其状态更改为故障状态，您可以通过多种方式检查此错误：

// Inside method MakeAsyncRequest
Task<WebResponse> task = Task.Factory.FromAsync(
    request.BeginGetResponse,
    asyncResult => request.EndGetResponse(asyncResult),
    (object)null);

// this 'task' object may fail and you should check it

return task.ContinueWith(
   t => 
     {
        if (t.Exception != null)
          FinishWebRequest(t.Result))

        // Not the best way to fault "continuation" task
        // but you can wrap this into your special exception
        // and add original exception as a inner exception
        throw t.Exception.InnerException;

        // throw CustomException("The request failed!", t.Exception.InnerException);
     };

在任何情况下，您都应该准备好任何任务都可能失败，因此您也应该使用相同的技术来处理生成的任务：

// outside method MakeAsyncRequest
var task = MakeAsyncRequest(string url);

task.ContinueWith(t => 
  // check tasks state or use TaskContinuationOption
  // handing error condition and result
);

try
{
  task.Wait(); // will throw
  Console.WriteLine(task.Result); // will throw as well
}
catch(AggregateException ae)
{
  // Note you should catch AggregateException instead of
  // original excpetion
  Console.WriteLine(ae.InnerException);
}
于 2012-12-03T18:59:52.640 回答