1

我有一个如何在 Oracle 中执行此操作？

select a.field1 || '_' || 
       b.field2 || '_' || 
       sum(c.field3)
  from table1 a, 
       table2 b, 
       table3 c
 where a.field1 || '_' || 
       b.field2 || '_' || 
       sum(c.field3) not in (select d.field1 || '_' || 
                                    e.field2 || '_' || 
                                    sum(f.field3)  
                               from table4 d, 
                                    table5 e, 
                                    table6 f
                              where conditional_info_to_join_the_tables 
                              group by d.field1, e.field2)
   and conditional_info_to_join_the_tables  
 group by a.field1, b.field2

我得到的错误是我不能在 where 子句中使用 sum

我试过使用

select a.field1 || '_' || 
       b.field2 || '_' || 
       sum(c.field3), 
       sum(c.field2) foo
  from table1 a, 
       table2 b, 
       table3 c
 where a.field1 || '_' || 
       b.field2 || '_' || 
       foo not in (select d.field1 || '_' || 
                          e.field2 || '_' || 
                          sum(f.field3)  
                     from table4 d, 
                          table5 e, 
                          table6 f
                    where conditional_info_to_join_the_tables 
                    group by d.field1, e.field2)
   and conditional_info_to_join_the_tables 
 group by a.field1, b.field2

但是那个 foo 不是一个已识别的变量。

4

2 回答 2

3

仅仅给出sum和别名 ( foo) 并没有帮助，因为聚合发生在过滤之后 (where子句.

该having子句就像在聚合之后应用的过滤器：

select a.field1 || '_' || b.field2 || '_' || sum(c.field3)
from table1 a, table2 b, table3 c
where conditional_info_to_join_the_tables
group by a.field1, b.field2
having a.field1 || '_' || b.field2 || '_' || sum(c.field3)
           not in ( select d.field1 || '_' || e.field2 || '_' || sum(f.field3) 
                    from table4 d, table5 e, table6 f
                    where conditional_info_to_join_the_tables 
                    group by d.field1, e.field2 )

您仍然需要完整地写出聚合而不是别名 - 这背后的原因不太明显，并且在 dba.se 上的这个答案中进行了讨论：https ://dba.stackexchange.com/a/21982/ 1396 .

当然，您可以使用子查询来实现相同的目的：

select foo
from( select a.field1 || '_' || b.field2 || '_' || sum(c.field3) as foo
      from table1 a, table2 b, table3 c
      where conditional_info_to_join_the_tables
      group by a.field1, b.field2 )
where foo not in ( select d.field1 || '_' || e.field2 || '_' || sum(f.field3) 
                   from table4 d, table5 e, table6 f
                   where conditional_info_to_join_the_tables 
                   group by d.field1, e.field2 )
于 2012-12-03T17:55:35.853 回答
0

您可以在没有所有连接的情况下执行此操作：

select abc.field1 || '_' || abc.field2 || '_' || sumf, 
       sum(c.field2) foo
from (select a.field1, b.field2, sum(c.field3) as sumf
      from a, b, c
      where conditional_info_to_join_the_tables
      group by a.field1, b.field2
     ) abc left outer join
     (select d.field1, e.field2, sum(f.field3) as sumf
      from d, e, f
      where conditional_info_to_join_the_tables
      group by d.field1, 3.field2
     ) def
     on abc.field1 = def.field1 and
        abc.field2 = def.field2 and
        abc.sumf = def.sumf
where def.field1 = NULL

一般来说，您应该使用更现代的join语法。这是一个left outer join非常合适的情况。

于 2012-12-03T18:58:43.340 回答