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我有一个简单的表单，我在其中设置了一个我想浏览的查询，例如panasonic viera。这是关于我如何在数据库中搜索该术语的：

Product.where("name ilike ?", "%#{params[:q]}%").order('price')

查询看起来像%panasonic viera%，但我需要以这种方式搜索查询：%panasonic%viera% - 我需要查找所有产品，标题中的单词panasonic或viera ... 但是如何制作这个查询？

4

4 回答 4

3

一种解决方案是将您的查询分解为单独的术语，并构建一组通过OR.

terms = params[:q].split
query = terms.map { |term| "name like '%#{term}%'" }.join(" OR ")
Product.where(query).order('price')
于 2012-12-03T14:33:53.703 回答
1

如果您使用的是 PostgreSQL，则可以使用pg_searchgem。它支持全文搜索，带有选项any_word：

Setting this attribute to true will perform a search which will return all models containing any word in the search terms.

示例来自pg_search：

class Number < ActiveRecord::Base
  include PgSearch
  pg_search_scope :search_any_word,
                  :against => :text,
                  :using => {
                    :tsearch => {:any_word => true}
                  }

  pg_search_scope :search_all_words,
                  :against => :text
end

one = Number.create! :text => 'one'
two = Number.create! :text => 'two'
three = Number.create! :text => 'three'

Number.search_any_word('one two three') # => [one, two, three]
Number.search_all_words('one two three') # => []
于 2012-12-03T14:33:45.473 回答
1

通过ARel怎么样

def self.search(query)
  words      = query.split(/\s+/)
  table      = self.arel_table
  predicates = []

  words.each do |word|
    predicates << table[:name].matches("%#{word}%")
  end

  if predicates.size > 1
    first = predicates.shift
    conditions = Arel::Nodes::Grouping.new(predicates.inject(first) {|memo, expr| Arel::Nodes::Or.new(memo, expr)})
  else
    conditions = predicates.first
  end

  where(conditions).to_a
end
于 2012-12-03T14:39:37.953 回答
0

这不工作？

 WHERE name LIKE "panasonic" OR name LIKE "viera"
于 2012-12-03T14:33:24.523 回答