我知道,这个问题以前曾多次以略有不同的方式提出。但我无法适应这些解决方案。我有一个包含以下内容的文件 header.out:
// some text before this
:type = "Primary Grid: Tau Format" ;
:deformation_timestep = 0. ;
:deformation_alpha = 0. ;
:deformation_dalpha = 0. ;
:deformation_h = 0. ;
:deformation_dh = 0. ;
:deformation_step = 0 ;
:adaptation_level = 0 ;
:connectivity_check = 1 ;
:volume_check = 1 ;
:point_check = 1 ;
:test_lib_check = 1 ;
:periodic_pairs_check = 1 ;
:is_balanced = 0 ;
:preserve_piles = 0 ;
:marker_1 = "WingMidTrailing" ;
:marker_2 = "WingMidLower" ;
:marker_3 = "WingMidUpper" ;
:marker_4 = "WingSide" ;
:marker_5 = "Farfield" ;
:marker_6 = "SymmetryPlane" ;
:marker_7 = "WingInnerLower" ;
:marker_8 = "WingInnerUpper" ;
:marker_9 = "WingInnerTrailing" ;
:marker_10 = "WingOuterLower" ;
:marker_11 = "WingOuterUpper" ;
:marker_12 = "WingOuterTrailing" ;
}
我需要提取属于字符串“SymmetryPlane”的标记的 ID 所以在这种情况下,我想要 6 作为输出。所有使用 sed 和正则表达式的尝试都失败了。我试过的是:
sed 's/.*marker_\(.*\) = "SymmetryPlane.*/\1/' header.out
但这只会给我
:type = "Primary Grid: Tau Format" ;
:deformation_timestep = 0. ;
:deformation_alpha = 0. ;
:deformation_dalpha = 0. ;
:deformation_h = 0. ;
:deformation_dh = 0. ;
:deformation_step = 0 ;
:adaptation_level = 0 ;
:connectivity_check = 1 ;
:volume_check = 1 ;
:point_check = 1 ;
:test_lib_check = 1 ;
:periodic_pairs_check = 1 ;
:is_balanced = 0 ;
:preserve_piles = 0 ;
:marker_1 = "WingMidTrailing" ;
:marker_2 = "WingMidLower" ;
:marker_3 = "WingMidUpper" ;
:marker_4 = "WingSide" ;
:marker_5 = "Farfield" ;
6
:marker_7 = "WingInnerLower" ;
:marker_8 = "WingInnerUpper" ;
:marker_9 = "WingInnerTrailing" ;
:marker_10 = "WingOuterLower" ;
:marker_11 = "WingOuterUpper" ;
:marker_12 = "WingOuterTrailing" ;
}
我不确定为什么会这样。
提前致谢!