sql - 添加 CASE 语句的结果

Question

我有以下 Oracle SQL 查询。给定一个给定的名字和姓氏，它会以任一顺序查找具有一个名字和另一个名字首字母的所有记录。我创建了score列以将可能的匹配项放在结果集的顶部。

SELECT
  surname,
  givenname,
  (CASE WHEN surname = 'Smith' THEN 2 ELSE 0)
    + (CASE WHEN givenname = 'John' THEN 1 ELSE 0)
    AS score
FROM person
WHERE (surname = 'Smith' AND givenname LIKE 'J%')
  OR  (surname LIKE 'S%' AND givenname = 'John')
  OR  (surname = 'John' AND givenname LIKE 'S%')
  OR  (surname LIKE 'J%' AND givenname = 'Smith')
ORDER BY
  score DESC,
  surname ASC,
  givenname ASC;

问题是score在+. IDE 报告：

语法错误，预期：
/
*
|

和执行报告：

SQL 错误：ORA-00905：缺少关键字

我究竟做错了什么？有没有更好的方法来计算分数？

Answer 1

您的陈述中缺少以下END内容：CASE

SELECT
  surname,
  givenname,
  (CASE WHEN surname = 'Smith' THEN 2 ELSE 0 END)  -- < add END
    + (CASE WHEN givenname = 'John' THEN 1 ELSE 0 END)  -- < add END
    AS score
FROM person
WHERE (surname = 'Smith' AND givenname LIKE 'J%')
  OR  (surname LIKE 'S%' AND givenname = 'John')
  OR  (surname = 'John' AND givenname LIKE 'S%')
  OR  (surname LIKE 'J%' AND givenname = 'Smith')
ORDER BY
  score DESC,
  surname ASC,
  givenname ASC;