我正在尝试制作一个发生在医院的小游戏。这是代码：
首先是标题：
#ifndef Hospital_Patient_h
#define Hospital_Patient_h
class Patient
{
public:
Patient();
bool cured();
bool died();
bool treatable();
void treat();
void untreated();
char consonant();
char vowel();
std::string getName();
int age;
int health;
std::string name;
bool operator==(const Patient &other)const;
};
#endif
这是cpp：
#include <iostream>
#include <string>
#include "Patient.h"
using namespace std;
char CONSONANTS[] =
{'b','c','d','f','g','h','j','k','l','m','n','p','r','s','t','v','z', '\0'};
char VOWELS[] =
{'a','e','i','o','u', '\0'};
//generates a patient with initial health, a name, and an age from 10-79
Patient::Patient()
{
int a= rand() % 80 + 10;
health= 50;
name= getName();
age= a;
}
bool Patient::cured() {
return health >= 100;
}
bool Patient::died() {
return health <= 0;
}
//treatable if not dead and not cured
bool Patient::treatable() {
return !died() && !cured();
}
void Patient::treat() {
if(treatable()) health= min(health + 10, 100);
}
void Patient::untreated() {
if(treatable()) health= max(health - 1, 0);
}
char Patient::consonant()
{
int index = rand() % 17; //CONSONANTS.size();
return CONSONANTS[index];//rand.nextInt(CONSONANTS.length)];
}
char Patient::vowel()
{
int index = rand() % 5; //VOWELS.size();
return VOWELS[index];//rand.nextInt(VOWELS.length)];
}
//generate a random name
string Patient::getName(){
string s;
s+=toupper(consonant());
s+= vowel();
s+=consonant();
s+=vowel();
if (rand() % 3 == 0) {
s+=consonant();
}
if (rand() % 3 == 0) {
s+=consonant();
s+=vowel();
}
s+=(' ');
s+=toupper(consonant());
s+=vowel();
if (rand() % 3 == 0) {
s+=consonant();
}
s+=consonant();
s+=vowel();
if (rand() % 3 == 0) {
s+=consonant();
}
if (rand() % 3 == 0) {
s+=consonant();
s+=vowel();
}
return s;
}
//overload ==
bool Patient::operator==(const Patient &other)const{
//compare each room's room number field
return (this->age == other.age && this->name == other.name);
}
到目前为止，在每个函数之后，我都收到一个错误，说“函数名称”的重新定义
我也遇到了构造函数和为标题中定义的变量赋值的问题。由于某种原因，标头也不喜欢 std:: ，我知道我永远不应该在标头中使用命名空间。