0

我希望有人能帮助我。我正在尝试解析以下 json 文件:

{
"seminar":[{
    "categoryid": "1",
    "cpe": "13",
    "inventory": [
        "Discussion",
        "Value x",
        "Value y"
    ],
    "teachers": [{
        "titel": "Dipl.-Ing.",
        "company": "XY",
        "name": "Test",
        "id": "3"
    }]
}]
}    

我在解析教师数据时迷失了......

private static final String TAG_TEACHERS = "teachers";
private static final String TAG_TITLE = "title";

for(int i = 0; i < seminar.length(); i++){
JSONObject c = seminar.getJSONObject(i);

teachers = c.getJSONArray(TAG_TEACHERS);
for(int z = 0; z < teachers.length(); z++){                 
JSONObject d = teachers.getJSONObject(z);
String title  = d.getString(TAG_TITLE);
Log.d("JSONParsingActivity", title);

我收到错误 System.err(1010): org.json.JSONException: org.json.JSONObject$1 类型的教师的 Value null 无法转换为 JSONArray。

我做错了什么?正如我从 JSON 文档中了解到的那样,教师是 JSON 数组而不是对象。有人可以帮助我吗?

4

3 回答 3

1

似乎您使用了错误的标签。教师 = c.getJSONArray(TAG_DOZENTEN);

不应该是 TAG_teachers 而不是 TAG_DOZENTEN 吗?

于 2012-12-02T19:03:06.163 回答
1

这可能不是您特定问题的答案,但无论如何。您需要手动解析吗?为什么不使用映射器,例如 Jackson。

http://jackson.codehaus.org/0.9.9/javadoc/org/codehaus/jackson/map/ObjectMapper.html

顺滑多了!

于 2012-12-02T19:03:36.303 回答
0

You can parse given JSON String as:

JSONObject jObject  = new JSONObject("YOUR_JSON_STRING");

JSONArray jArrseminar = jObj.getJSONArray("seminar");
for(int i = 0; i < jArrseminar.length(); i++){
    JSONObject jobject = jArrseminar.getJSONObject(i);

    String strcategoryid=jobject.getString("categoryid");
    String strcpe=jobject.getString("cpe");

    JSONArray jArrinventory = jobject.getJSONArray("inventory");
    for(int j = 0; j < jArrinventory.length(); j++){

        // access all inventory value here
    }


    JSONArray jArrteachers = jobject.getJSONArray("teachers");
    for(int j = 0; j < jArrteachers.length(); j++){
        JSONObject jobjectteachers = jArrteachers.getJSONObject(i);

        // access all teachers value here
    String strtitel=jobjectteachers.getString("titel");
    String strcompany=jobjectteachers.getString("company");
    String strname=jobjectteachers.getString("name");
    String strid=jobjectteachers.getString("id");
    }
}
于 2012-12-02T19:12:31.920 回答