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我想将数据从 xml 文件保存到我的数据库，在下面你可以看到我的 php 代码，我试图在其中创建一个关联数组以将值放入以供以后使用。但是，实际的 SimpleXMLElement 对象被存储，而不仅仅是纯值。

我在这里有两个问题：

  1. 如何更改我的代码以便存储实际值（作为数字或字符串）而不是 SimpleXMLElement 对象？
  2. 这是存储值以供以后使用 SQLLite（我将使用）存储的好方法，还是我有哪些其他选项效果更好？

php:

$theProducers = simplexml_load_file('sources/producers.xml');

$i = 0;
foreach ($theProducers->producer as $producer) {
    $producers['id'][$i] = $producer->attributes();
    $producers['name'][$i] = $producer->name;
    $producers['address'][$i] = $producer->address;
    $producers['zipcode'][$i] = $producer->zipcode;
    $producers['town'][$i] = $producer->town;
    $producers['url'][$i] = $producer->url;
    $producers['imgurl'][$i] = $producer->imgurl;

    $i += 1;
}

print_r($producers);  // outcome below

生产者.xml：

<?xml version="1.0"?>
<producers>
  <producer id="8">
    <name>Em&#xE5;mejeriet</name>
    <address>Grenv&#xE4;gen 1-3</address>
    <zipcode>577 39</zipcode>
    <town>Hultsfred</town>
    <url>http://www.emamejeriet.se</url>
    <imgurl>http://172.16.206.1/~thajo/1DV449/laboration01/producenter/images/ema.png</imgurl>
  </producer>
  <producer>
  ...

print_r($producers) 的结果：

Array (
[id] => Array (
    [0] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 8 ) )
    [1] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 57 ) )
    [2] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 45 ) )
    [3] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 33 ) )
    [4] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 16 ) )
    [5] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 41 ) )
    [6] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 38 ) )
    [7] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 40 ) )
    [8] => SimpleXMLElement Object ( [@attributes] => Array ( [id] => 56 ) ) )
[name] => Array (
    [0] => SimpleXMLElement Object ( [0] => Emåmejeriet )
    [1] => SimpleXMLElement Object ( [0] => Ölands Örtagård AB )
    [2] => SimpleXMLElement Object ( [0] => Dövestads utegrisar & Gårdsbutik )
... and so on...
4

2 回答 2

2

改变输出数组的结构：

foreach ($theProducers->producer as $producer) {
    $attr = $producer->attributes();
    $producers[$i]['id'] = (int)$attr[0];
    $producers[$i]['name'] = (string)$producer->name;
    $producers[$i]['address'] = (string)$producer->address;
    $producers[$i]['zipcode'] = (string)$producer->zipcode;
    $producers[$i]['town'] = (string)$producer->towbn;
    $producers[$i]['url'] = (string)$producer->url;
    $producers[$i]['imgurl'] = (string)$producer->imgurl;

    $i += 1;
}
于 2012-12-02T18:31:02.387 回答
1

只需转换为适当的数据类型（例如，通常string，但有时其他类型，如int，可能有意义）：

$producers['id'][$i] = (string)$producer->attributes()['id'];
$producers['name'][$i] = (string)$producer->name;
$producers['address'][$i] = (string)$producer->address;
$producers['zipcode'][$i] = (string)$producer->zipcode;
$producers['town'][$i] = (string)$producer->town;
$producers['url'][$i] = (string)$producer->url;
$producers['imgurl'][$i] = (string)$producer->imgurl;

注意：我也加入['id']了->attributes()通话——假设这是您的意图。

于 2012-12-02T18:39:10.270 回答