1

我不知道为什么我不能用正确的方法来用 if 和 else if 语句来编码我的简单计算。

所有变量都只返回一个“0.0”值，我猜不出有什么问题？你能帮我解决这个问题吗？

这是我的代码：

public class MonthlyComputation extends MyActivity
{
String civil_status;

public void DoComputation()
{

    final EditText net_salary = (EditText) findViewById(R.id.et_net_monthly);
    final EditText tax_due = (EditText) findViewById(R.id.et_taxdue);
    final Button btn_compute = (Button) findViewById(R.id.btn_compute_from_monthly);
    final TextView txt3 = (TextView) findViewById(R.id.textView3);
    final TextView txt4 = (TextView) findViewById(R.id.textView4);

    final TextView txt5 = (TextView) findViewById(R.id.textView5);
    final TextView txt6 = (TextView) findViewById(R.id.textView6);


    btn_compute.setOnClickListener(new Button.OnClickListener()
    {

        @Override
        public void onClick(View v)
        {

            double netSalary, taxDue, rate = 0, exemption = 0, subtrahend = 0, withRate;
            String ns, td, r, e, s, wr;

            ns = net_salary.getText().toString();
            netSalary = Double.parseDouble(ns);

            /* Single or Married with no dependent */

            if ((civil_status == "SME") && (netSalary >= 4167) && (netSalary < 5000))
            {
                rate = 0.05;
                exemption = 0.00;
                subtrahend = 4167;
            }

            else if ((civil_status == "SME") && (netSalary >= 5000) && (netSalary < 6667))
            {
                rate = 0.1;
                exemption = 41.67;
                subtrahend = 5000;
            }

            taxDue = netSalary - subtrahend;
            withRate = taxDue * rate;
            taxDue = withRate + exemption;
            tax_due.setText(Double.toString(taxDue));

            td = String.valueOf(taxDue);
            e = String.valueOf(exemption);
            s = String.valueOf(subtrahend);
            r = String.valueOf(rate);

            txt3.setText(td);
            txt4.setText(e);
            txt5.setText(s);
            txt6.setText(r);

        }
    });
}
4

1 回答 1

12

永远不要用来==比较String（和一般的对象），你很可能会得到false，因为它比较对象引用，而不是值。

有关更多信息，请参阅其他问题：Java String.equals 与 ==

解决方案？改用.equals()：

...
if ("SME".equals(civil_status) && (netSalary >= 4167) && (netSalary < 5000))
{
    rate = 0.05;
    exemption = 0.00;
    subtrahend = 4167;
}
...
于 2012-12-02T15:56:15.503 回答