我正在尝试在我的应用程序中实现聊天模块。我参考了 QuickBlox API 的简单示例代码。
但是当我尝试从我的应用程序注册用户时，我得到了以下链接器错误。
我的代码： -
// Create QuickBlox User entity
QBUUser *user = [QBUUser user];
user.password = _textPassword.text;
user.login = [DicResponse valueForKey:@"User name"];
// create User
[QBUsers signUp:user delegate:self];
在我的应用程序中，我已经在使用ASIHTTP库。如果我评论这一行[QBUsers signUp:user delegate:self];，那么它编译成功。
如何解决这种冲突？
duplicate symbol _isDismissing in: /Users/abc/Library/Developer/Xcode/DerivedData/app-dtliqcvxngqgfwgzpbvmtupglcjd/Build/Intermediates/app.build/Debug-iphonesimulator/app.build/Objects-normal/i386/ASIAuthenticationDialog.o /Projects/abc/Quickblox.framework/Quickblox(QBASIAuthenticationDialog.o) duplicate symbol _NetworkRequestErrorDomain in: /Users/abc/Library/Developer/Xcode/DerivedData/app-dtliqcvxngqgfwgzpbvmtupglcjd/Build/Intermediates/app.build/Debug-iphonesimulator/app.build/Objects-normal/i386/ASIHTTPRequest.o /Projects/LockMEIfYouCan/Quickblox.framework/Quickblox(QBASIHTTPRequest.o) duplicate symbol _RedirectionLimit in: /Users/abc/Library/Developer/Xcode/DerivedData/app-dtliqcvxngqgfwgzpbvmtupglcjd/Build/Intermediates/app.build/Debug-iphonesimulator/app.build/Objects-normal/i386/ASIHTTPRequest.o /Projects/app/Quickblox.framework/Quickblox(QBASIHTTPRequest.o) ld: 3 duplicate symbols for architecture i386