5

我需要帮助来了解如何仅显示每个分支最常见的产品。

这适用于数据库中的每个分支。

PS:这是在一张表中完成的(本次表演不需要其他表),只需要提到的两个属性。

4

2 回答 2

1

根据 Sean 的 DB 示例,我创建了查询,它可以完成这项工作,但是请注意,您在应用程序中的运行方式看起来很耗费资源。尝试考虑另一种方法来发现最常见的产品,而不是数据库查询。

SELECT 
    a.branch_id, `branch_product` , COUNT(branch_product) AS cnt , b.mx
FROM 
    branch_products a 
LEFT JOIN 
    (SELECT 
        branch_id, MAX(cnt) AS mx 
     FROM 
        (SELECT branch_id, COUNT(branch_product) AS cnt FROM branch_products GROUP BY branch_id, branch_product ) AS maxes 
     GROUP BY branch_id) b 
ON a.branch_id = b.branch_id
GROUP BY branch_id, branch_product
HAVING cnt=mx
于 2012-12-04T10:13:32.260 回答
0

将计数放在子查询中,按计数 DESC 排序,然后在该子查询之外按分支 ID 分组:

SELECT * FROM (
    SELECT *, count(branch_product) AS cou FROM branch_products
    GROUP BY branch_id, branch_product
    ORDER BY cou DESC
) AS ordbycou
GROUP BY branch_id

产量:

+-----------+----------------+-----+
| branch_id | branch_product | cou |
+-----------+----------------+-----+
|         1 | trainers       |   3 |
|         2 | suit           |   2 |
|         3 | suit           |   1 |
+-----------+----------------+-----+
3 rows in set (0.00 sec)

这是一个示例表,用于尝试上述查询:

SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO";
CREATE TABLE IF NOT EXISTS `branch_products` (
  `branch_id` mediumint(8) unsigned NOT NULL,
  `branch_product` varchar(128) NOT NULL,
  KEY `branch_id` (`branch_id`),
  KEY `branch_product` (`branch_product`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1;
INSERT INTO `branch_products` (`branch_id`, `branch_product`) VALUES
(1, 'trainers'),
(1, 'trainers'),
(1, 'trainers'),
(1, 'tie'),
(1, 'tie'),
(1, 'suit'),
(2, 'suit'),
(2, 'suit'),
(2, 'tie'),
(3, 'suit');
于 2012-12-02T05:51:45.813 回答