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我用函数写了一个简单的计算器程序，我不知道这段代码到底有什么问题，它显示错误。我做了可能的步骤来调试它，但我做不到。

#!/usr/bin/python

def add():        
        print "Enter the two numbers to Add"
        A=int(raw_input("Enter A:"))
        B=int(raw_input("ENter B:"))
        c = A + B 

def sub():            
        print "Enter the two numbers to Subtract"
        A=int(raw_input("Enter A:"))
        B=int(raw_input("Enter B:"))
        c = A - B

def Mul():
        print "Enter the two numbers to Multiply"
        A=int(raw_input("Enter A:"))
        B=int(raw_input("Enter B:"))
        c = A * B

def Div():   
        print "Enter the two number to Divide"
        A=float(raw_input("Enter A:"))
        B=float(raw_input("Enter B:"))
        c = A / B

print "1: ADDITION"
print "2: SUBTRACTION"
print "3: MULTIPLICATION"
print "4: DIVITION"
print "0: QUIT"

while true:

    CHOICE = int(raw_input(("ENTER THE CORRESPONDING NUMBER FOR CALCULATION")) 

    if CHOICE == "1": 
        print 'ADDING TWO NUMBERS:'
        add(c):

    elif CHOICE == "2":
        print 'SUBTRACTING TWO NUMBERS:'
        sub(c):

    elif CHOICE == "3":
        print 'MULTIPLYING TWO NUMBERS:'
        Mul(c):

    elif CHOICE == "4":
        print "DIVIDEING TWO NUMBERS"
        Div(c):

    elif CHOICE == "0":
        return 0:

    else
        Print "The value Enter value from 1-4"

错误：

  File "cal_fun.py", line 44
    if CHOICE == "1": 
                  ^
SyntaxError: invalid syntax
4

4 回答 4

4

我已经尝试涵盖您的代码的所有问题，其中有很多。

从syntax错误开始：

# true needed a captial T
while True:   

    # Brackets were mismatched
    CHOICE = int(raw_input("ENTER THE CORRESPONDING NUMBER FOR CALCULATION")) 

    if CHOICE == "1": 
        print 'ADDING TWO NUMBERS:'
        # Calling a function shouldn't have trailing : 
        add(c)

    elif CHOICE == "2":
        print 'SUBTRACTING TWO NUMBERS'
        # Calling a function shouldn't have trailing :
        sub(c)

    elif CHOICE == "3":
        print 'MULTIPLYING TWO NUMBERS'
        # Calling a function shouldn't have trailing :
        Mul(c)

    elif CHOICE == "4":
        print "DIVIDEING TWO NUMBERS"
        # Calling a function shouldn't have trailing :
        Div(c)

    elif CHOICE == "0":
        # can only return from a function use exit here instead
        exit()

    # else needs a trailing :
    else:
        # No capital P for print
        print "The value Enter value from 1-4"

代码现在没有syntax错误，但仍然有很多问题。

  1. 你传递c给你的函数，c永远不会初始化，什么是c？
  2. 您的函数不接受参数def add(): （即使传递了神秘的c值）。
  3. 您的函数没有print或return它只是计算的结果。
  4. 您将存储CHOICE为int与字符串进行比较，因此else始终执行案例并且无法退出循环（无限循环）。

固定代码：

#!/usr/bin/python

def add():
        print "Enter the two numbers to Add"
        A=int(raw_input("Enter A: "))
        B=int(raw_input("Enter B: "))
        return A + B 

def sub():
        print "Enter the two numbers to Subtract"
        A=int(raw_input("Enter A: "))
        B=int(raw_input("Enter B: "))
        return A - B

def mul():
        print "Enter the two numbers to Multiply"
        A=int(raw_input("Enter A: "))
        B=int(raw_input("Enter B: "))
    return A * B

def div():
        print "Enter the two number to Divide"
        A=float(raw_input("Enter A: "))
        B=float(raw_input("Enter B: "))
        return A / B

print "1: ADDITION"
print "2: SUBTRACTION"
print "3: MULTIPLICATION"
print "4: DIVITION"
print "0: QUIT"

while True:

    CHOICE = int(raw_input("ENTER THE CORRESPONDING NUMBER FOR CALCULATION ")) 

    if CHOICE == 1: 
        print 'ADDING TWO NUMBERS:'
        print add()

    elif CHOICE == 2:
        print 'SUBTRACTING TWO NUMBERS'
        print sub()

    elif CHOICE == 3:
        print 'MULTIPLYING TWO NUMBERS'
        print mul()

    elif CHOICE == 4:
        print "DIVIDEING TWO NUMBERS"
        print div()

    elif CHOICE == 0:
        exit()
    else:
        print "The value Enter value from 1-4"

代码现在可以正常工作了。

输出：

1: ADDITION
2: SUBTRACTION
3: MULTIPLICATION
4: DIVITION
0: QUIT
ENTER THE CORRESPONDING NUMBER FOR CALCULATION 1
ADDING TWO NUMBERS:
Enter the two numbers to Add
Enter A: 2
Enter B: 5
7
ENTER THE CORRESPONDING NUMBER FOR CALCULATION 2
SUBTRACTING TWO NUMBERS
Enter the two numbers to Subtract
Enter A: 2
Enter B: 5
-3
ENTER THE CORRESPONDING NUMBER FOR CALCULATION 3
MULTIPLYING TWO NUMBERS
Enter the two numbers to Multiply
Enter A: 2
Enter B: 5
10
ENTER THE CORRESPONDING NUMBER FOR CALCULATION 4
DIVIDEING TWO NUMBERS
Enter the two number to Divide
Enter A: 2
Enter B: 5
0.4
ENTER THE CORRESPONDING NUMBER FOR CALCULATION 0

功能性但不完美，例如对错误输入没有错误处理。

于 2012-12-01T23:27:22.773 回答
1

您在上一行缺少一个结束括号（神秘语法错误的常见原因），更改：

CHOICE = int(raw_input(("ENTER THE CORRESPONDING NUMBER FOR CALCULATION"))

至

CHOICE = int(raw_input("ENTER THE CORRESPONDING NUMBER FOR CALCULATION"))

这不是程序中唯一的语法错误——你:在不应该的时候结束了很多行，比如：

    add(c):
    sub(c):
    Mul(c):
    Div(c):

你也

  1. 没有声明（这是必需的:）else
  2. Print应该大写print
  3. 在任何函数之外都有一个 return 语句

还有一些不是语法错误的错误：

  1. 拼写错误True为true
  2. 比较CHOICE，一个 int，到一个字符串，如"1"or"2"
  3. 将不存在的变量传递给不c带参数的函数
于 2012-12-01T23:22:47.473 回答
1

您正在将变量传递c给您的函数add() sub()等，但它们被定义为不带参数。

于 2012-12-01T23:28:13.050 回答
1

除了已经提到的语法错误之外，我认为您真正想要的是每个函数将值返回到主程序循环，然后将显示它们：

def add():
    A=int(raw_input("Enter A:"))
    B=int(raw_input("ENter B:"))
    return A + B
...

while true:

    CHOICE = int(raw_input(("ENTER THE CORRESPONDING NUMBER FOR CALCULATION")) 

    if CHOICE == "1": 
        print 'ADDING TWO NUMBERS:'
        answer = add()
        print answer
    ...

或者通过在主循环中输入 A 和 B 然后将它们作为参数传递给计算函数来缩短程序：

def add():
    return A + B
...

while true:

    CHOICE = int(raw_input(("ENTER THE CORRESPONDING NUMBER FOR CALCULATION")) 
    A=int(raw_input("Enter A:"))
    B=int(raw_input("ENter B:"))
    if CHOICE == "1": 
        print 'ADDING TWO NUMBERS:'
        answer = add(A, B)
        print answer
    ...
于 2012-12-01T23:40:45.553 回答