我有一个 java 程序,当在 JPanel 中单击鼠标右键时会打开一个弹出菜单。单击任何弹出菜单项时,我想打印在终端中触发弹出菜单的右键单击位置。我该怎么做呢?如何从弹出操作事件中获取右键单击的位置?
如果弹出菜单在 JComponent 中,代码如何更改?
这是程序。
import java.awt.EventQueue;
import java.awt.event.*;
import javax.swing.*;
public class MenuTest
{
public static void main(String[] args)
{
EventQueue.invokeLater(new Runnable()
{
public void run()
{
MenuFrame frame = new MenuFrame();
frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
frame.setVisible(true);
}
});
}
}
class MenuFrame extends JFrame
{
public MenuFrame()
{
setTitle("MenuTest");
setSize(300, 200);
Action cutAction = new TestAction("Cut");
Action copyAction = new TestAction("Copy");
Action pasteAction = new TestAction("Paste");
JPopupMenu popup = new JPopupMenu();
popup.add(cutAction);
popup.add(copyAction);
popup.add(pasteAction);
JPanel panel = new JPanel();
panel.setComponentPopupMenu(popup);
add(panel);
panel.addMouseListener(new MouseAdapter() {});
}
class TestAction extends AbstractAction
{
public TestAction(String name)
{
super(name);
}
public void actionPerformed(ActionEvent event)
{
System.out.println("Right click happened at ?"); // How do I get right click location?
}
}
}