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我正在编写一个程序，该程序应该对比赛中的竞争者进行排名和排序。

# Defining class. Also sorts the array elements in ascending order.
class Dancer
attr_reader :couplenumber
attr_reader :scores
def initialize(couplenumber,scores)
@couplenumber=couplenumber
@scores=scores.sort
end 
end

# Opening file, and sorting into array. Also splits with ",".
results = File.open("danceresult.txt", "r+")
dancescores=[]
results.each do |result|
scores = result.split(',').map(&:to_i) 
couplenumber = scores.shift
dancescores << Dancer.new(couplenumber, scores)
end
dancescores.each do |dancers|
  dancers.scores
  # Prints to screen.
  puts "Couple No. #{dancers.couplenumber} got "\
       "a minimum score of #{dancers.scores[3]} or better. "\
       "Their sum is: #{dancers.scores[0..3].inject(:+)}"
end

我希望总和Their sum is: #{dancers.scores[0..3].inject(:+)}只取最低分数最低的那些。所以如果我们有五个竞争者，其中两个最低得分为 2，另外三个最低得分为 4，那么“总和部分”应该只取最低得分为 2 的竞争者。是否可能没有重新编写所有代码，如果是这样，最简单的方法是什么？

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1 回答 1

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首先确定最低分数是多少：

min_score = dancescores.map{|d| d.scores[3]}.min

然后在打印之前添加一个条件：

dancescores.each do |dancer|
  # Prints to screen if the couple has the min_score
  if dancer.scores[3] == min_score
    puts "Couple No. #{dancer.couplenumber} got "\
       "a minimum score of #{dancer.scores[3]} or better. "\
       "Their sum is: #{dancer.scores[0..3].inject(:+)}"
  end
end

或者您可以使用select仅处理具有 min_score 的那些舞者，如下所示：

dancescores.select{|d| d[3] == min_score}.each do |dancer|
  puts "Couple No. #{dancer.couplenumber} got "\
     "a minimum score of #{dancer.scores[3]} or better. "\
     "Their sum is: #{dancer.scores[0..3].inject(:+)}"
end
于 2012-12-01T14:45:05.533 回答