好的,从我所看到的情况来看,使用 passport.js 是有效的,而且效果很好。但是,我不确定如何正确排除某些用户。如果应用程序旨在限制访问,而不仅仅是为用户提供登录方法,我该如何限制通过 passport.js 登录?就目前而言,用户只需访问/login
并使用他们的 Google 帐户登录,就可以访问内部。
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2 回答
9
这是执行此操作的一种方法,并在整个过程中提供评论。主要是从作者那里理解这个页面:http: //passportjs.org/guide/authenticate/,我在这个例子中解释了一点......
从下到上阅读可能更容易:
var authenticate = function(req, success, failure) {
// Use the Google strategy with passport.js, but with a custom callback.
// passport.authenticate returns Connect middleware that we will use below.
//
// For reference: http://passportjs.org/guide/authenticate/
return passport.authenticate('google',
// This is the 'custom callback' part
function (err, user, info) {
if (err) {
failure(err);
}
else if (!user) {
failure("Invalid login data");
}
else {
// Here, you can do what you want to control
// access. For example, you asked to deny users
// with a specific email address:
if (user.emails[0].value === "no@emails.com") {
failure("User not allowed");
}
else {
// req.login is added by the passport.initialize()
// middleware to manage login state. We need
// to call it directly, as we're overriding
// the default passport behavior.
req.login(user, function(err) {
if (err) {
failure(err);
}
success();
});
}
}
}
);
};
一个想法是将上面的代码包装在更多的中间件中,以使其更易于阅读:
// This defines what we send back to clients that want to authenticate
// with the system.
var authMiddleware = function(req, res, next) {
var success = function() {
res.send(200, "Login successul");
};
var failure = function(error) {
console.log(error);
res.send(401, "Unauthorized");
};
var middleware = authenticate(req, success, failure);
middleware(req, res, next);
};
// GET /auth/google/return
// Use custom middleware to handle the return from Google.
// The first /auth/google call can remain the same.
app.get('/auth/google/return', authMiddleware);
(这一切都假设我们使用的是 Express。)
于 2012-12-06T00:02:33.277 回答
0
试试这个。
googleLogin: function(req, res) {
passport.authenticate('google', { failureRedirect: '/login', scope: ['https://www.googleapis.com/auth/plus.login', 'https://www.googleapis.com/auth/userinfo.profile', 'https://www.googleapis.com/auth/userinfo.email'] }, function(err, user) {
req.logIn(user, function(err) {
if (err) {
console.log(err);
res.view('500');
return;
}
var usrEmail = user['email'];
if(usrEmail.indexOf("@something.com") !== -1)
{
console.log('successful');
res.redirect('/');
return;
}
else
{
console.log('Invalid access');
req.logout();
res.view('403');
return;
}
});
})(req, res);
}
*
于 2014-12-16T10:37:18.243 回答