31

我已经尝试了几种解决方案，比如一个 ->

http://www.pcreview.co.uk/forums/console-writeline-hangs-if-user-click-into-console-window-t1412701.html

但是，我观察到 GetConsoleMode(IntPtr hConsoleHandle, out int mode) 中的模式对于不同的控制台应用程序会有所不同。它不是一成不变的。

我可以在控制台应用程序上禁用鼠标单击（右/左按钮）以实现相同的场景。我发现它可以使用 IMessageFilter 完成，但仅适用于窗口窗体应用程序，而不适用于控制台应用程序。

请指导。

4

6 回答 6

73

对于像我这样喜欢简单地复制/粘贴代码的人，这里是受接受答案启发的代码：

using System;
using System.Runtime.InteropServices;

static class DisableConsoleQuickEdit {

   const uint ENABLE_QUICK_EDIT = 0x0040;

   // STD_INPUT_HANDLE (DWORD): -10 is the standard input device.
   const int STD_INPUT_HANDLE = -10;

   [DllImport("kernel32.dll", SetLastError = true)]
   static extern IntPtr GetStdHandle(int nStdHandle);

   [DllImport("kernel32.dll")]
   static extern bool GetConsoleMode(IntPtr hConsoleHandle, out uint lpMode);

   [DllImport("kernel32.dll")]
   static extern bool SetConsoleMode(IntPtr hConsoleHandle, uint dwMode);

   internal static bool Go() {

      IntPtr consoleHandle = GetStdHandle(STD_INPUT_HANDLE);

      // get current console mode
      uint consoleMode;
      if (!GetConsoleMode(consoleHandle, out consoleMode)) {
         // ERROR: Unable to get console mode.
         return false;
      }

      // Clear the quick edit bit in the mode flags
      consoleMode &= ~ENABLE_QUICK_EDIT;

      // set the new mode
      if (!SetConsoleMode(consoleHandle, consoleMode)) {
         // ERROR: Unable to set console mode
         return false;
      }

      return true;
   }
}
于 2016-04-19T14:06:03.623 回答
17

如果要禁用快速编辑模式，则需要调用GetConsoleMode来获取当前模式。然后清除启用快速编辑的位，并调用SetConsoleMode。假设您有非托管函数的托管原型，您将编写：

const int ENABLE_QUICK_EDIT = 0x0040;

IntPtr consoleHandle = GetConsoleWindow();
UInt32 consoleMode;

// get current console mode
if (!GetConsoleMode(consoleHandle, out consoleMode))
{
    // Error: Unable to get console mode.
    return;
}

// Clear the quick edit bit in the mode flags
mode &= ~ENABLE_QUICK_EDIT;

// set the new mode
if (!SetConsoleMode(consoleHandle, consoleMode))
{
    // ERROR: Unable to set console mode
}

如果要禁用鼠标输入，则要清除鼠标输入位。

const int ENABLE_MOUSE_INPUT = 0x0010;

mode &= ~ENABLE_MOUSE_INPUT;
于 2012-12-01T06:09:29.620 回答
8

阅读上述答案后，无法使用 GetConsoleWindow()。而是必须使用 GetStdHandle()。

所以这里有一个用于启用/禁用 QuickEditMode 的复制和粘贴类。调用ConsoleWindow.QuickEditMode(false); 禁用控制台窗口的快速编辑模式。

using System;
using System.Runtime.InteropServices;

public static class ConsoleWindow
{
    private static class NativeFunctions
    {
        public enum StdHandle : int
        {
            STD_INPUT_HANDLE = -10,
            STD_OUTPUT_HANDLE = -11,
            STD_ERROR_HANDLE = -12,
        }

        [DllImport("kernel32.dll", SetLastError = true)]
        public static extern IntPtr GetStdHandle(int nStdHandle); //returns Handle

        public enum ConsoleMode : uint
        {
            ENABLE_ECHO_INPUT = 0x0004,
            ENABLE_EXTENDED_FLAGS = 0x0080,
            ENABLE_INSERT_MODE = 0x0020,
            ENABLE_LINE_INPUT = 0x0002,
            ENABLE_MOUSE_INPUT = 0x0010,
            ENABLE_PROCESSED_INPUT = 0x0001,
            ENABLE_QUICK_EDIT_MODE = 0x0040,
            ENABLE_WINDOW_INPUT = 0x0008,
            ENABLE_VIRTUAL_TERMINAL_INPUT = 0x0200,

            //screen buffer handle
            ENABLE_PROCESSED_OUTPUT = 0x0001,
            ENABLE_WRAP_AT_EOL_OUTPUT = 0x0002,
            ENABLE_VIRTUAL_TERMINAL_PROCESSING = 0x0004,
            DISABLE_NEWLINE_AUTO_RETURN = 0x0008,
            ENABLE_LVB_GRID_WORLDWIDE = 0x0010
        }

        [DllImport("kernel32.dll", SetLastError = true)]
        public static extern bool GetConsoleMode(IntPtr hConsoleHandle, out uint lpMode);

        [DllImport("kernel32.dll", SetLastError = true)]
        public static extern bool SetConsoleMode(IntPtr hConsoleHandle, uint dwMode);
    }

    public static void QuickEditMode(bool Enable)
    {
        //QuickEdit lets the user select text in the console window with the mouse, to copy to the windows clipboard.
        //But selecting text stops the console process (e.g. unzipping). This may not be always wanted.
        IntPtr consoleHandle = NativeFunctions.GetStdHandle((int)NativeFunctions.StdHandle.STD_INPUT_HANDLE);
        UInt32 consoleMode;

        NativeFunctions.GetConsoleMode(consoleHandle, out consoleMode);
        if (Enable)
            consoleMode |= ((uint)NativeFunctions.ConsoleMode.ENABLE_QUICK_EDIT_MODE);
        else
            consoleMode &= ~((uint)NativeFunctions.ConsoleMode.ENABLE_QUICK_EDIT_MODE);

        consoleMode |= ((uint)NativeFunctions.ConsoleMode.ENABLE_EXTENDED_FLAGS);

        NativeFunctions.SetConsoleMode(consoleHandle, consoleMode);
    }
}
于 2018-11-20T11:17:12.037 回答
1

对于那些使用 vb.net

Const ENABLE_QUICK_EDIT As UInteger = &H40
Const STD_INPUT_HANDLE As Integer = -10


   <DllImport("kernel32.dll", SetLastError:=True)>
Public Function GetStdHandle(ByVal nStdHandle As Integer) As IntPtr
End Function

<DllImport("kernel32.dll")>
Private Function GetConsoleMode(ByVal hConsoleHandle As IntPtr, <Out> ByRef lpMode As UInteger) As Boolean
End Function

<DllImport("kernel32.dll")>
Private Function SetConsoleMode(ByVal hConsoleHandle As IntPtr, ByVal dwMode As UInteger) As Boolean
End Function 

    Friend Function Go() As Boolean
    Dim consoleHandle As IntPtr = GetStdHandle(STD_INPUT_HANDLE)
    Dim consoleMode As UInteger

    If Not GetConsoleMode(consoleHandle, consoleMode) Then
        Return False
    End If

    consoleMode = consoleMode And Not ENABLE_QUICK_EDIT

    If Not SetConsoleMode(consoleHandle, consoleMode) Then
        Return False
    End If

    Return True
End Function

sub main()
go()
end sub
于 2021-07-12T19:32:58.533 回答
0

通过使用下面的代码组合，我可以启用或禁用快速编辑模式。

const int ENABLE_QUICK_EDIT = 0x0040;

// STD_INPUT_HANDLE (DWORD): -10 is the standard input device.
const int STD_INPUT_HANDLE = -10;

[DllImport("kernel32.dll", SetLastError = true)]
static extern IntPtr GetStdHandle(int nStdHandle);

[DllImport("kernel32.dll")]
static extern bool GetConsoleMode(IntPtr hConsoleHandle, out int lpMode);

[DllImport("kernel32.dll")]
static extern bool SetConsoleMode(IntPtr hConsoleHandle, int dwMode);

要启用，简单做currentConsoleMode &= ENABLE_QUICK_EDIT;

要禁用，请执行 currentConsoleMode &= ~ENABLE_QUICK_EDIT

然后调用SetConsoleMode。

于 2015-10-30T18:06:58.943 回答
-1

我碰巧在我的控制台应用程序中启用了快速编辑模式时偶然发现了同样的问题，该应用程序是用 C 编写的，并且多年来一直在 windows 7 32 位下工作。在将其移植（不是真正的移植，而是调整了一些代码行）到 Windows 10 64 位（仍然是 32 位应用程序）之后，我观察到了相同的行为。所以我寻找解决方案。

但是由于我不知道的原因，代码的工作方式相反，即ENABLE_QUICK_EDIT_MODE在模式参数中设置该位实际上会禁用快速编辑模式。并重置位启用快速编辑模式......？？？

这是我的代码：

    /// <summary>
/// This flag enables the user to use the mouse to select and edit text. To enable
/// this option, you must also set the ExtendedFlags flag.
/// </summary>
const int QuickEditMode = 64;

// ExtendedFlags must be combined with
// InsertMode and QuickEditMode when setting
/// <summary>
/// ExtendedFlags must be enabled in order to enable InsertMode or QuickEditMode.
/// </summary>
const int ExtendedFlags = 128;

BOOLEAN EnableQuickEdit()
{
    HWND conHandle = GetStdHandle(STD_INPUT_HANDLE);
    int mode;
    DWORD dwLastError = GetLastError();
    if (!GetConsoleMode(conHandle, &mode))
    {
        // error getting the console mode. Exit.
        dwLastError = GetLastError();
        return (dwLastError == 0);
    }
    else 
        dwLastError = 0;
    mode = mode & ~QuickEditMode;

    if (!SetConsoleMode(conHandle, mode | ExtendedFlags))
    {
        // error setting console mode.
        dwLastError = GetLastError();
    }
    else
        dwLastError = 0;
    return (dwLastError == 0);
}

BOOLEAN DisableQuickEdit()
{
    HWND conHandle = GetStdHandle(STD_INPUT_HANDLE);
    int mode;
    DWORD dwLastError = GetLastError();

    if (!GetConsoleMode(conHandle, &mode))
    {
        // error getting the console mode. Exit.
        dwLastError = GetLastError();
        return (dwLastError == 0);
    }
    else
        dwLastError = 0;

    mode = mode | QuickEditMode;

    if (!SetConsoleMode(conHandle, mode))
    {
        // error getting the console mode. Exit.
        dwLastError = GetLastError();
    }
    else
        dwLastError = 0;
    return (dwLastError == 0);
}

问候沃尔夫冈

于 2019-01-22T12:02:39.423 回答