1

我在论坛上找到了以下课程代码。它适用于游戏手柄（上、下、左、右），但按钮的所有代码都丢失了。任何人都可以填空吗？

这有效：

Private Sub joystick1_Up() Handles joystick1.Up
    moveUp()
End Sub

这不会：

Private Sub joystick1_buttonPressed() Handles joystick1.buttonPressed
    MsgBox(joystick1.btnValue)
End Sub

因为没有“buttonPressed”事件，我不知道怎么写。

这是课程：

Imports System.ComponentModel
Imports System.Runtime.InteropServices


Public Class joystick
    Inherits NativeWindow

    Private parent As Form
    Private Const MM_JOY1MOVE As Integer = &H3A0

    ' Public Event Move(ByVal joystickPosition As Point)
    Public btnValue As String
    Public Event Up()
    Public Event Down()
    Public Event Left()
    Public Event Right()

    <StructLayout(LayoutKind.Explicit)> _
    Private Structure JoyPosition
        <FieldOffset(0)> _
        Public Raw As IntPtr
        <FieldOffset(0)> _
        Public XPos As UShort
        <FieldOffset(2)> _
        Public YPos As UShort
    End Structure

    Private Class NativeMethods

        Private Sub New()
        End Sub

        ' This is a "Stub" function - it has no code in its body.
        ' There is a similarly named function inside a dll that comes with windows called
        ' winmm.dll. 
        ' The .Net framework will route calls to this function, through to the dll file.
        <DllImport("winmm", CallingConvention:=CallingConvention.Winapi, EntryPoint:="joySetCapture", SetLastError:=True)> _
        Public Shared Function JoySetCapture(ByVal hwnd As IntPtr, ByVal uJoyID As Integer, ByVal uPeriod As Integer, <MarshalAs(UnmanagedType.Bool)> ByVal changed As Boolean) As Integer
        End Function

    End Class

    Public Sub New(ByVal parent As Form, ByVal joyId As Integer)
        AddHandler parent.HandleCreated, AddressOf Me.OnHandleCreated
        AddHandler parent.HandleDestroyed, AddressOf Me.OnHandleDestroyed
        AssignHandle(parent.Handle)
        Me.parent = parent
        Dim result As Integer = NativeMethods.JoySetCapture(Me.Handle, joyId, 100, True)
    End Sub

    Private Sub OnHandleCreated(ByVal sender As Object, ByVal e As EventArgs)
        AssignHandle(DirectCast(sender, Form).Handle)
    End Sub

    Private Sub OnHandleDestroyed(ByVal sender As Object, ByVal e As EventArgs)
        ReleaseHandle()
    End Sub

    Protected Overrides Sub WndProc(ByRef m As System.Windows.Forms.Message)
        If m.Msg = MM_JOY1MOVE Then
            ' Joystick co-ords.
            ' (0,0) (32768,0) (65535, 0) 
            '
            '
            '
            ' (0, 32768) (32768, 32768) (65535, 32768)
            '
            '
            '
            '
            ' (0, 65535) (32768, 65535) (65535, 65535)
            '

            Dim p As JoyPosition
            p.Raw = m.LParam
            ' RaiseEvent Move(New Point(p.XPos, p.YPos))
            If p.XPos > 16384 AndAlso p.XPos < 49152 Then
                ' X is near the centre line.
                If p.YPos < 6000 Then
                    ' Y is near the top.
                    RaiseEvent Up()
                ElseIf p.YPos > 59536 Then
                    ' Y is near the bottom.
                    RaiseEvent Down()
                End If
            Else
                If p.YPos > 16384 AndAlso p.YPos < 49152 Then
                    ' Y is near the centre line
                    If p.XPos < 6000 Then
                        ' X is near the left.
                        RaiseEvent Left()
                    ElseIf p.XPos > 59536 Then
                        ' X is near the right
                        RaiseEvent Right()
                    End If
                End If
            End If
        End If
        If btnValue <> m.WParam.ToString Then
            btnValue = m.WParam.ToString
        End If
        MyBase.WndProc(m)
    End Sub

End Class
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1 回答 1

2

我不会使用较旧的 winmm，而是使用 XInput（或者如果可以，使用 XNA）。

有几种方法可以做到这一点。一个步骤是直接使用MSDN 论坛上这个问题所概述的 XInput dll 。不过，这仍然相当丑陋。可能“更简单”的方法是使用存在的包装库，如SlimDX或SharpDX。

通过 SlimDX 或 SharpDX 使用 XInput 的优点之一是它也可以在 Windows 8 的 Windows 应用商店应用程序中工作:)。

这是SharpDX 中 GamePad 示例的片段：

C＃

var controllers = new[] { new Controller(UserIndex.One), new Controller(UserIndex.Two), new Controller(UserIndex.Three), new Controller(UserIndex.Four) };

// Get 1st controller available 
Controller controller = null; 
foreach (var selectControler in controllers) 
{ 
    if (selectControler.IsConnected) 
    { 
        controller = selectControler; 
        break; 
    }
}

VB

Dim controllers As New List(Of Controller)
controllers.Add(New Controller(UserIndex.One))
controllers.Add(New Controller(UserIndex.Two))
controllers.Add(New Controller(UserIndex.Three))
controllers.Add(New Controller(UserIndex.Four))

Dim controller as Controller = Nothing; 
For Each selectController In controllers
    If selectController.IsConnected Then
        controller = selectController
        Exit For
    End If
Next

然后，您可以使用以下方法使状态正常工作：

var state = controller.GetState();

您会注意到 XInput 使用了更多的轮询模型，因此您需要偶尔检查按钮按下以检测到这一点。如果您需要连续轮询，您可能可以启动一个新任务来执行此操作。

于 2012-12-07T00:32:05.783 回答