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为了编写这段代码，我检查并使用了一些教程，但我仍然失败了，考虑到只有 main 函数似乎工作并以代码 0 退出。我的踏板不是创建的吗？它们是但不知何故我未能将它们与我的“工作”功能联系起来？

#include <stdio.h>
#include <stdlib.h>
#include <pthread.h>
#include <unistd.h>
#include <math.h>


struct node { // std linked list node
    int value;
    int worker;
    struct node *next;
};
// pthread_t* w_thread;

int slots = 3; // only 3 threads are allowed to access the list
int availableCheck(){   // check if thread can acces the list
    if(slots < 3) return 0;
    else return -1;
}

pthread_mutex_t mutp = PTHREAD_MUTEX_INITIALIZER;   //condvar mutex
pthread_cond_t  condvar = PTHREAD_COND_INITIALIZER;   //condvar

void * worker( void *i ){
    long index = (long)i;
    printf( "    * I am worker  # %lu : \n",pthread_self() );
    // pthread_mutex_lock( &mutp );
    // if(availableCheck() < 0){
        // printf( " ^^^ List not available yet... \n" ); 
        // pthread_cond_wait( &condvar, &mutp );
    printf( "* Got data:  %lu \n", index ); 
    // pthread_cond_signal( &condvar ); // 
    // pthread_mutex_unlock( &mutp ); 

    return NULL;
    // }
}

int main( int argc, char *argv[] ){
    if ( argc != 3 ){
        printf( "Programm must be called with \n NR of elements and NR of workers! \n " );
        exit( 1 );
    }

    int i,listSize,workersSize;
    struct node *root;
    struct node *iterator;  

//prepare list for task
    listSize = atoi(argv[1]);
    root = malloc(sizeof( struct node) );

    root->value = rand() % 100;
    // printf(">>> %d\n", root->value );
    root->worker = 0;

    iterator = malloc(sizeof(struct node) );
    iterator = root;

    for( i=1; i<listSize; i++ ){
        iterator->next = malloc(sizeof(struct node));
        iterator = iterator->next;
        iterator->value = rand() % 100;
        iterator->worker = i;
        printf("node #%d worker: %d  value: %d\n", i, iterator->worker,iterator->value);
    }
    printf("? List got populated\n");

// Create all threads to parse the link list
    int ret;    
    pthread_t w_thread;
    int nrWorkers = atoi(argv[2]);
    pthread_t* w_threads = malloc(nrWorkers * sizeof(w_thread));
    for( i=0; i<listSize; i++ ){
        int *id = malloc(sizeof(int));
        *id = i;
         ret = pthread_create ( &w_threads[i], NULL, worker, (void *) &id );
         if( ret ) {
            perror("Thread creation fail");
            exit(2);    
        }
    } 
    int j;
    for (j = 0; i < nrWorkers; j++){
        pthread_join(w_threads[j],NULL);
    }       
}

Ps一些注释函数/变量将被使用/实现，但在这一点上我希望线程

4

1 回答 1

2

我怀疑在你创建线程的 for 循环中你应该有：

 for( i=0; i<nWorkers; i++ ){

另外，我建议您为输入参数添加检查/打印。

还有一个问题：你将指针传递给worker()，所以你必须取消引用指针，如果它是指向int的指针，那么

void * worker( void *p_int ){
    assert(p_int != NULL)   
    int index = *(int*)p_ind;

从 void* 投射要准确！

最后一件事。如果您知道 listSize，我不清楚您为什么要创建链接列表：

for( i=1; i<listSize; i++ ){
    iterator->next = malloc(sizeof(struct node));
    iterator = iterator->next;
    ...

相反，您可以仅在一行代码中分配您的数组，而无需为root分配：

p_list = (struct node*)malloc(listSize*sizeof(struct node));
assert(p_list);
for( i=0; i<listSize; i++ ){
    p_list[i].value = ...
    ...

如您所见，这里不需要下一个指针。

于 2012-11-30T22:37:46.163 回答