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我有两张桌子,一张有一组团队和有关他们的信息。另一张表有关于他们玩过的游戏的信息。我想计算一个特定球队打了多少场比赛。

我在一张名为 team 的表上有 team_number、team_name。我在名为played 的另一张表上有played_team,它是team_number 的外键。

我如何编写一个连接来计算 play_team 的出现次数并使用 team_number 和 team_name 加入它?

我正在使用 MYSQL 5.1,我希望这是有道理的。谢谢

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1 回答 1

1

怎么样:

select teams.`team_name`, count(matches.`played_team`) 
from teams 
join matches on teams.`team_number` = matches.`played_team` 
group by teams.`team_name`

以下是我使用的表格:

CREATE TABLE `teams` (
  `team_number` int(11) NOT NULL AUTO_INCREMENT,
  `team_name` varchar(30) DEFAULT NULL,
  PRIMARY KEY (`team_number`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

INSERT INTO `teams` (`team_number`, `team_name`)
VALUES
    (1,'a'),
    (2,'b'),
    (3,'c'),
    (4,'d');

CREATE TABLE `matches` (
  `played_team` int(11) NOT NULL,
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `match_title` varchar(30) DEFAULT NULL,
  PRIMARY KEY (`id`),
  KEY `played_team` (`played_team`),
  CONSTRAINT `matches_ibfk_1` FOREIGN KEY (`played_team`) REFERENCES `teams` (`team_number`)
) ENGINE=InnoDB DEFAULT CHARSET=latin1;

INSERT INTO `matches` (`played_team`, `id`, `match_title`)
VALUES
    (1,1,'match_a'),
    (1,2,'match_b'),
    (3,3,'match_c'),
    (4,4,'match_d');

以下是查询的结果:

team_name    count(matches.`played_team`)  
a            2  
c            1  
d            1
于 2012-11-29T21:19:10.500 回答