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任何人？？？？嗨，在我的二十一点游戏中，我通过首先要求玩家加倍下注来实现拆分，如果他拒绝，那么我允许他拆分：

while(true){
    for(int j=0;j<2;j++){
        if(players[i].splits[j].getStatus() != true){ // splits is an array of two players hand 1 and hand 2
            System.out.print("Choose your next move, " + players[i].name + ", Hand "+ players[i].splits[j].number + ": \n" + "Points: " + players[i].splits[j].points + "\n" + "Hint: ");
            getHints(players[i].splits[j]);
            System.out.print( "\n1)Hit\n2)Stand\n");
            System.out.println();

            x2 = IO.readInt();
            if (x2==2){
                players[i].splits[j].standed = true; // if player stand...
                break;
            }else if(x2 == 1){//else deal a card
                Card c = dealCard(deck);
                updatePoints(players[i].splits[j], c);
                addCard(players[i].splits[j], c);
                System.out.println(players[i].name + ", Hand "+ players[i].splits[j].number + " was dealt:  " + c.showCardValue() + " of " + c.showCardSuit() );
                boolean isBusted = testPoints(players[i].splits, j); // test for busted
                if (isBusted == true){
                    System.out.println("BUSTED!!!!!!!!!");
                    players[i].splits[j].busted = true;
                    break;
                }
            }
        }
        System.out.println(players[i].name + ", Hand " + players[i].splits[j].number + " Points: "+ players[i].splits[j].points);
//                                          printStats(players[i].splits[j]);

    }
//check to end loop if split is busted to stands...
}

当我打印球员统计数据时，我得到的是内存位置而不是文本，任何人都可以帮忙。谢谢，如果您需要更多信息，请告诉我，以便我更新。

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输出： 3 是玩家姓名... 10 是分牌发牌...

Choose your next move, 3, Hand 1: 
Points: 10
Hint: You have a 0% chance of busting
1)Hit
2)Stand

1
3, Hand 1 was dealt:  Ten of Spades
3, Hand 1 Points: 20
Choose your next move, 3, Hand 2: 
Points: 10
Hint: You have a 0% chance of busting
1)Hit
2)Stand

1
3, Hand 2 was dealt:  Five of Diamonds
3, Hand 2 Points: 15
Choose your next move, 3, Hand 1: 
Points: 20
Hint: You have a 92% chance of busting
1)Hit
2)Stand

2
3, Hand 1 Points: 20
Choose your next move, 3, Hand 2: 
Points: 15
Hint: You have a 58% chance of busting
1)Hit
2)Stand

2
3, Hand 1 : Points splitPlayer@1a758cb
Previous Cards dealt: 
Ten of Spades 

Five of Diamonds

splitPlayer 类：

public class splitPlayer {

    public int points = 0;
    boolean busted = false;
    boolean standed = false;
    int number = 0;
    int ace = 0;
    String name = "";
    Card[] cardsDealt = new Card[12];


    public splitPlayer(int number, int points){
        this.number = number;
        this.name = "Hand "+ number;
        this.points = points;
    }
    public boolean getStatus(){
        if(busted == true || standed == true ){
            return true;
        }else{
            return false;
        }
    }
    public void setPoints(int points){
        this.points += points;
    }
}

=========

更新点：

public static void updatePoints(splitPlayer player,  Card c){

        int point = c.getValue();

        if (point == 1){


            player.ace += 1;
            player.setPoints(11);


        }else{
            player.setPoints(point);
        }

        if (player.points > 21 && player.ace > 0) {
            player.points -= 10;
            player.ace --;
        }





        return;
    }
4

1 回答 1

1

罪魁祸首似乎是这行代码：

System.out.println(players[i].name + ", Hand " + players[i].splits[j].number + " Points: "+ players[i].splits[j].points);

要找出问题所在，您需要知道类型players[i].splits[j].points是什么。根据输出，它似乎是splitPlayer该类的一个实例。您可能可以通过重载toString()此类的方法来解决问题。如果不确认上述代码行确实导致了问题，我无法确定。我还需要查看更多您的代码，特别points是此处使用的数据成员的声明。

附录：

您在输出中看到的原因splitPlayer@1a758cb是因为您将对象与String. Java会自动调用toString()对象的方法。如果对象的类没有提供toString()方法，Object则会调用 in 提供您看到的输出的方法。

于 2012-11-29T00:48:06.977 回答