这是可以预料的。在处理像这样的内存数组时,Oracle 将假设该表中有 8k 行。
试试这个来帮助它:
SELECT /*+ cardinality(t, 20) */ count(*) into l_result FROM project p JOIN TABLE(in_project_ids) t ON p.project_id = t.val;
其中 20 应该是对实际条目数的粗略猜测。这是提示“可以”(并且需要帮助优化器)的边缘情况之一。
编辑
例如:
SQL> explain plan for SELECT /*+ cardinality(t, 1) */ * FROM project p JOIN TABLE(VARCHAR20_TABLE()) t ON p.project_id = t.val;
Explained.
SQL> select * From table(dbms_xplan.display);
Plan hash value: 858605789
--------------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
--------------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 1 | 27 | 30 (0)| 00:00:01 |
| 1 | NESTED LOOPS | | | | | |
| 2 | NESTED LOOPS | | 1 | 27 | 30 (0)| 00:00:01 |
| 3 | COLLECTION ITERATOR CONSTRUCTOR FETCH| | 1 | 2 | 29 (0)| 00:00:01 |
|* 4 | INDEX UNIQUE SCAN | SYS_C0011177 | 1 | | 0 (0)| 00:00:01 |
| 5 | TABLE ACCESS BY INDEX ROWID | PROJECT | 1 | 25 | 1 (0)| 00:00:01 |
--------------------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
4 - access("P"."PROJECT_ID"=TO_NUMBER(SYS_OP_ATG(VALUE(KOKBF$),1,2,2)))
Note
-----
- dynamic sampling used for this statement (level=2)
21 rows selected.
SQL> explain plan for SELECT * FROM project p JOIN TABLE(VARCHAR20_TABLE()) t ON p.project_id = t.val;
Explained.
SQL> select * From table(dbms_xplan.display);
Plan hash value: 583089723
--------------------------------------------------------------------------------------------------
| Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time |
--------------------------------------------------------------------------------------------------
| 0 | SELECT STATEMENT | | 8168 | 215K| 33 (4)| 00:00:01 |
|* 1 | HASH JOIN | | 8168 | 215K| 33 (4)| 00:00:01 |
| 2 | TABLE ACCESS FULL | PROJECT | 2000 | 50000 | 3 (0)| 00:00:01 |
| 3 | COLLECTION ITERATOR CONSTRUCTOR FETCH| | 8168 | 16336 | 29 (0)| 00:00:01 |
--------------------------------------------------------------------------------------------------
Predicate Information (identified by operation id):
---------------------------------------------------
1 - access("P"."PROJECT_ID"=TO_NUMBER(SYS_OP_ATG(VALUE(KOKBF$),1,2,2)))
Note
-----
- dynamic sampling used for this statement (level=2)
19 rows selected.
一个简单的例子,但请注意集合 fetch = 8168 上的“行”,没有提示和计划的更改。检查解释计划与真实表与集合与提示集合,并有帮助,使用合理的基数提示数,您的计划和性能应该得到改善。