kendo-ui - 刷新单个剑道网格行

Question

有没有办法在不刷新整个数据源或使用 jQuery 为每个单元格设置值的情况下刷新单个 Kendo 网格行？

Answer 1

您如何定义要更新的行？我将假设这是您选择的行，并且正在更新的列的名称是symbol.

// Get a reference to the grid
var grid = $("#my_grid").data("kendoGrid");

// Access the row that is selected
var select = grid.select();
// and now the data
var data = grid.dataItem(select);
// update the column `symbol` and set its value to `HPQ`
data.set("symbol", "HPQ");

请记住， 的内容DataSource是一个observable对象，这意味着您可以使用它来更新它set，并且更改应该神奇地反映在grid.

Answer 2

data.set在某些情况下，实际上会刷新整个网格并发送databound事件。这是非常缓慢且不必要的。它还将折叠任何不理想的扩展详细信息模板。

我建议您使用我编写的这个函数来更新剑道网格中的单行。

// Updates a single row in a kendo grid without firing a databound event.
// This is needed since otherwise the entire grid will be redrawn.
function kendoFastRedrawRow(grid, row) {
    var dataItem = grid.dataItem(row);

    var rowChildren = $(row).children('td[role="gridcell"]');

    for (var i = 0; i < grid.columns.length; i++) {

        var column = grid.columns[i];
        var template = column.template;
        var cell = rowChildren.eq(i);

        if (template !== undefined) {
            var kendoTemplate = kendo.template(template);

            // Render using template
            cell.html(kendoTemplate(dataItem));
        } else {
            var fieldValue = dataItem[column.field];

            var format = column.format;
            var values = column.values;

            if (values !== undefined && values != null) {
                // use the text value mappings (for enums)
                for (var j = 0; j < values.length; j++) {
                    var value = values[j];
                    if (value.value == fieldValue) {
                        cell.html(value.text);
                        break;
                    }
                }
            } else if (format !== undefined) {
                // use the format
                cell.html(kendo.format(format, fieldValue));
            } else {
                // Just dump the plain old value
                cell.html(fieldValue);
            }
        }
    }
}

例子：

// Get a reference to the grid
var grid = $("#my_grid").data("kendoGrid");

// Access the row that is selected
var select = grid.select();
// and now the data
var data = grid.dataItem(select);

// Update any values that you want to
data.symbol = newValue;
data.symbol2 = newValue2;
...

// Redraw only the single row in question which needs updating
kendoFastRedrawRow(grid, select);

// Then if you want to call your own databound event to do any funky post processing:
myDataBoundEvent.apply(grid);

Answer 3

我找到了一种更新网格数据源并在网格中显示而不刷新所有网格的方法。例如，您有一个选定的行，并且您想更改列“名称”的值。

//the grid
var grid = $('#myGrid').data('kendoGrid');    
// Access the row that is selected
var row = grid.select();
//gets the dataItem
var dataItem = grid.dataItem(row);
//sets the dataItem   
dataItem.name = 'Joe';
//generate a new row html
var rowHtml = grid.rowTemplate(dataItem);
//replace your old row html with the updated one
row.replaceWith(rowHtml);

Answer 4

updateRecord(record) {
    const grid = $(this.el.nativeElement).data('kendoGrid');
    const row = grid.select();
    const dataItem = grid.dataItem(row);
    for (const property in record) {
      if (record.hasOwnProperty(property)) {
        dataItem.set(property, record[property]);
      }
    }
  }