21

提交连接表单时出现此错误(我使用 FOSUserBundle 最新版本):

No encoder has been configured for account "MyApp\UtilisateurBundle\Entity\Utilisateur

这是我的实体:

    <?php
namespace MyApp\UtilisateurBundle\Entity;
use FOS\UserBundle\Entity\User as BaseUser;
use Doctrine\ORM\Mapping as ORM;
/**
 * @ORM\Entity
 */
class Utilisateur extends BaseUser
{
    /**
    * @ORM\Id
    * @ORM\Column(type="integer")
    * @ORM\generatedValue(strategy="AUTO")
    */
    protected $id;
    public function __construct()
    {
        parent::__construct();
    }

    /**
     * Get id
     *
     * @return integer 
     */
    public function getId()
    {
        return $this->id;
    }
}

这是我的 app/config/security.yml :

imports:
- { resource: "@MyAppFilmothequeBundle/Resources/config/security.yml" }

这是我的 src/MyApp/FilmothequeBundle/Ressources/config/security.yml :

security:
providers:
    fos_userbundle:
        id: fos_user.user_manager

firewalls:
    main:
        pattern:      .*
        form_login:
            provider:       fos_userbundle
            login_path:     /myapp/login
            use_forward:    false
            check_path:     /myapp/login_check
            failure_path:   null
            default_target_path: /myapp
        logout:
            path:   /myapp/logout
            target: /myapp
        anonymous:    true

我按照本教程这样做:http: //j-place.developpez.com/tutoriels/php/ameliorez-vos-applications-developpees-avec-symfony2/#LVI-B-1

我怎样才能做到这一点?先感谢您

4

3 回答 3

50

尝试将此添加到 security.yml 中的安全密钥

encoders:
        FOS\UserBundle\Model\UserInterface: sha512

所以这是

security:
    encoders:
        FOS\UserBundle\Model\UserInterface: sha512

    providers:
        ...

    firewalls:
        ...
于 2012-11-28T14:49:20.057 回答
3

我在LexikJWTAuthenticationBundle上收到此错误。

它对我有帮助(config/packages/security.yaml):

security:
    encoders:
      App\Entity\User:
        algorithm: bcrypt
于 2018-12-11T20:35:39.323 回答
2

您需要在 security.yml 中添加此代码

    encoders:
        # use your user class name here
        App\Entity\User:
            # Use native password encoder
            # This value auto-selects the best possible hashing algorithm
            # (i.e. Sodium when available).
            algorithm: auto

我使用 symfony 4.4

为我工作

于 2020-05-26T17:47:49.820 回答