2

我是一名 android 开发人员，目前使用 PHP 在 GCM 服务器端工作。从我的客户端，我将 gcm 响应令牌存储在一个数据库中，现在我想一次性向注册用户发送消息。我不知道该怎么做，我完全糊涂了。我的简单 HTML 文件是：

<html>
<head>
<title>
GCM
</title>
</head>
<body topmargin="50" leftmargin="50" CLASS = "bg">
<form action="send_message.php" name="myform" method="post">
<h4>Admin for sending notificaion to the registered user</h4>
Notification Text: <input name="appText" size="15" type="text"/><br>
URL: <input name="url" size="15" type="text" /><br>
<button type="submit">Submit</button>
</form>
</body>
</html>

而且，我的 send_message.php：

<?php
error_reporting (0);

$link = mysql_connect("localhost","db","db"); 
if (!$link) 
 { 
 die(mysql_error()) ; 
 } 
mysql_select_db("gcm_user")or die(mysql_error());
........................................
.....................................
.....................................
?>

现在，在 php 文件中我应该做什么，我已经尝试过这个链接Android Hive example

只是，现在通过这个链接。请建议我如何使用此解决方案解决我的问题。我的问题的新链接。

但我只想要一个 php 用于我的目的。请帮助克服这个 prm。

4

2 回答 2

4

回答我自己的问题。这是我为满足我的要求所做的。

$gcm_text = $_POST['gcmText'];
$gcm_url = $_POST['gcmURL'];
$gcm_subText = $_POST['gcm_secondText'];

$sql = "select gcm_response_token as regId from GCM";
$result = mysql_query($sql);

while ($row = mysql_fetch_assoc($result)) {
    $gcm_array[]=$row['regId'];
    $counter++;
}

mysql_free_result($result);


    $body['allsearch'] = array(
            'gcmText' => $gcm_text,
            'gcm_secondText' => $gcm_subText,
            'gcmURL' => $gcm_url
            );

    // Set POST variables
  $url = 'https://android.googleapis.com/gcm/send';

  $fields = array(
 'registration_ids' => $gcm_array,
 'data' => $body,
 );

//echo GOOGLE_API_KEY;
 $headers = array(
 'Authorization: key=$apiKey',
  'Content-Type: application/json'
 );


print_r($headers);
// Open connection
$ch = curl_init();

// Set the url, number of POST vars, POST data
curl_setopt($ch, CURLOPT_URL, $url);

curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_HTTPHEADER, $headers);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);

// Disabling SSL Certificate support temporarly
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);

curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode($fields));

// Execute post
$result = curl_exec($ch);
if ($result === FALSE) {
    die('Curl failed: ' . curl_error($ch));
}

// Close connection
curl_close($ch);
echo $result;

?>

通过这种方式，我能够将 json 数据发送到客户端并获得通知。

于 2012-11-30T06:24:55.377 回答
2

这些链接似乎使 PHP 过于复杂。您要做的就是用查询中的值填充该 $registrationIDs 数组。我不是 PHP 专家，但我使用了经常引用的 CURL 示例并准备了如下语句：

   $ttl = 86400;
   $randomNum=rand(10,100); 
   $registrationIDs = array();
   .....

   $queryregid = "select regid from registrations where  YOUR SPECIFIC CRITERIA......";
   if (!($stmt = $mysqli->prepare( $queryregid))) {
      echo "Prepare failed: (" . $mysqli->errno . ") " . $mysqli->error; }
   if (!$stmt->execute()) {  
      echo "Execute failed: (" . $stmt->errno . ") " . $stmt->error; }
   if (!$stmt->bind_result($dev_i)){  
      echo "bind failed: (" . $stmt->errno . ") " . $stmt->error;  }

   /* fetch values */
   while ($stmt->fetch()) {
      $regidOne =  $dev_i;
      $registrationIDs[] = $regidOne; // Fill the array
   }
   $stmt->close();

   $fields = array(
           'registration_ids' => $registrationIDs,
             'data' => array( "message" => $message),
             'delay_while_idle'=> false,
             'time_to_live' => $ttl,
             'collapse_key'=>"".$randomNum.""
            );
   $headers = array(
        'Authorization: key=' . $apiKey,
         'Content-Type: application/json'
         );

   // Open connection
   $ch = curl_init();

   // Set the url, number of POST vars, POST data
  curl_setopt( $ch, CURLOPT_URL, $url );
  curl_setopt( $ch, CURLOPT_POST, true );
  curl_setopt( $ch, CURLOPT_HTTPHEADER, $headers);
  curl_setopt( $ch, CURLOPT_RETURNTRANSFER, true );
  curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
  curl_setopt($ch, CURLOPT_POSTFIELDS, json_encode( $fields ));

   // Execute post
   $result = curl_exec($ch);
   // Close connection
   curl_close($ch);

.

于 2012-11-28T08:02:22.403 回答