php - 将 JSON 解析数组转换为 CSV

Question

首先，我看到了 The Other Threads，我认为它们都不是使用 PHP 或 javascript。

好吧，在我编码并添加斜杠以转义 JSON 非法字符后，我有了这个数组：

"#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12" "#Tahrir","2012-Oct-12"  "#Tahrir","2012-Oct-19" "#Tahrir","2012-Oct-19" "#Tahrir","2012-Oct-19"

想要将其更改为 CSV 或找到一种方法将此示例与该图一起使用：http: //bl.ocks.org/3883245#data.tsv

提前致谢。

Answer 1

要将 json 数据转换为 CSV，请尝试使用此http://jsfiddle.net/sturtevant/vUnF9/（不是我的代码）

function JSON2CSV(objArray) {
var array = typeof objArray != 'object' ? JSON.parse(objArray) : objArray;

var str = '';
var line = '';

if ($("#labels").is(':checked')) {
    var head = array[0];
    if ($("#quote").is(':checked')) {
        for (var index in array[0]) {
            var value = index + "";
            line += '"' + value.replace(/"/g, '""') + '",';
        }
    } else {
        for (var index in array[0]) {
            line += index + ',';
        }
    }

    line = line.slice(0, -1);
    str += line + '\r\n';
}

for (var i = 0; i < array.length; i++) {
    var line = '';

    if ($("#quote").is(':checked')) {
        for (var index in array[i]) {
            var value = array[i][index] + "";
            line += '"' + value.replace(/"/g, '""') + '",';
        }
    } else {
        for (var index in array[i]) {
            line += array[i][index] + ',';
        }
    }

    line = line.slice(0, -1);
    str += line + '\r\n';
}
return str;
}