c++ - 如何将文本（诗歌）拆分为行（字符串/字符 []）并查找每行的最后一个单词

Question

我有一首诗，例如：

    Roses are red
    Violets are blue
    Sugar is sweet
    And so are you

仅用 /n 分隔，我需要获取每一行的最后一个单词，以便找到朋友建议使用这个的最后一个单词：

string lastWord(string line)
{
    return line.substr(max(line.rfind(" "), 0));
}

但是将文本分成几行呢？

Answer 1

But what about splitting text into lines?

The answer depends on where the text is initially: if the entire text is in a file, use ifstream; if the text is in a string, use stringstream. In both cases, use getline in a loop to extract lines from the text one-by-one:

string poem = "Roses are red\n\
Violets are blue\n\
Sugar is sweet\n\
And so are you";
stringstream ss(poem);
string line;
while (getline(ss, line)) {
    cout << lastWord(line) << endl;
}

Also, your lastWord function has an off-by-one error: you should simply add one to the result of rfind, rather than using max, like this:

string lastWord(string line)
{
    return line.substr(line.rfind(" ")+1);
}

This will remove the initial space from the word being returned.

Answer 2

I would use a split function. See also: http://www.dotnetperls.com/split

Answer 3

substr只要您有换行符，就可以循环调用。

请记住，换行符可能会因平台、'\n'Linux/OSX 和"\r\n"Windows 的不同而有所不同。