1

我在 main 之前声明了结构：

struct roomData
{
  float widthFeet, widthInch;
  float lengthFeet, lengthInch;
  char roomName[100];
  int roomNumberOfType;
  char roomType[6]; //char of room type
  int roomStock[101][6]; //for storing each room stock types
  int roomHasStock; //if the room has a stock avaliable
  int roomStockCount; //how many stocks the room has
  float area;  // sq ft
  float rentalRate;
  float profitsPerRoom;
  float netProfit;
  float grossProfit;
};

在 main 里面，我用这个声明结构：

int main(void)
{
struct roomData rooms[MAXROOMS+1] = {0}; //struct for rooms(+1 for temp swapping in sorts)
}

稍后我将结构和其他一些变量传递给一个函数，并在 main 中使用以下代码：

        fillRoomData(n, x, array, rooms, 1);

fillRoomData 函数是这样的：

    void fillRoomData(int n, int x, struct fileInput array[300], struct roomData rooms[MAXROOMS], int check)//NEED TO ERROR CHECK
{
    if(check == 1) //for stock values in room
    {
        char * word4; //for strTok
        word4 = strtok(array[n].input," "); //stockType
        rooms[x].roomStock[a][0] = atoi(word4); //sores stock number
        word4 = strtok(NULL, " "); //stockCount
        rooms[x].roomStock[a][1] = atoi(word4); //sores stock inventory
....

}

这是我在 rdb 之后从 GCC 得到的错误

    Program received signal SIGSEGV, Segmentation fault.
0x000000338f23473a in ____strtoll_l_internal () from /lib64/libc.so.6
(gdb) backtrace
#0  0x000000338f23473a in ____strtoll_l_internal () from /lib64/libc.so.6
#1  0x000000338f231bf2 in atoi () from /lib64/libc.so.6
#2  0x0000000000406ed9 in fillRoomData (n=29, x=0, array=0x7ffffffefcc0, 
    rooms=0x7ffffffd2fe0, check=1) at amp6572Lab4.c:1420
#3  0x0000000000400fde in main () at amp6572Lab4.c:279
(gdb) frame 2
#2  0x0000000000406ed9 in fillRoomData (n=29, x=0, array=0x7ffffffefcc0, 
    rooms=0x7ffffffd2fe0, check=1) at amp6572Lab4.c:1420
    1420                rooms[x].roomStock[a][b] = atoi(word4); //stores

非常感谢所有的帮助！

4

1 回答 1

0

尝试将您的主要更改为：

struct roomData rooms[MAXROOMS+1];
于 2012-11-27T13:29:06.977 回答