我想要查询以“yy 年 mm 月 dd 天”格式查找员工的经验。
SELECT EMPID, EMPNAME, DEPARTMENT, DESIGNATION, DATEDIFF(YEAR, DOJ, GETDATE()) AS EXPERIENCE,
EMPSTATUS AS JOB_STATUS
FROM EMPLOYEE
DOJ - 数据库中用于保存员工“加入日期”的字段。这是仅返回年经验的查询。如何修改它？
问问题
48432 次
6 回答
1
SELECT
EMPID, EMPNAME, DEPARTMENT, DESIGNATION,
convert(varchar(3),DATEDIFF(MONTH, DOJ, GETDATE())/12) +' years '+
convert(varchar(2),DATEDIFF(MONTH, DOJ, GETDATE()) % 12)+ ' months'
AS EXPERIENCE,
EMPSTATUS AS JOB_STATUS
FROM EMPLOYEE
于 2012-11-27T08:24:40.727 回答
1
将 Emp_joiningDate 视为列
SELECT DATEDIFF(year, Emp_joiningDate, GETDATE()) AS Years,
DATEDIFF(month, Emp_joiningDate, GETDATE()) - DATEDIFF(year, '1/2/1999', GETDATE()) * 12 AS Months,
DATEDIFF(day, Emp_joiningDate, getdate())- DATEDIFF(month, '1/2/1999',
GETDATE()) - DATEDIFF(year, '1/2/1999', GETDATE()) * 365 as Days
于 2014-06-24T08:30:25.647 回答
0
用于测试的SQL Fiddle
SELECT EMPID, EMPNAME, DEPARTMENT, DESIGNATION,
cast(floor(experience / 365) as varchar) + ' years ' +
cast(floor(experience % 365 / 30) as varchar) + ' months ' +
cast(experience % 30 as varchar) + ' days' as experience,
EMPSTATUS AS JOB_STATUS
FROM (select *, datediff(DAY, doj, getdate()) as experience
from employee) t
于 2012-11-27T08:30:08.820 回答
0
DECLARE @FromDate DATETIME = '2013-12-01 23:59:59.000',
@ToDate DATETIME = '2016-08-30 00:00:00.000',
DECLARE @MONTHS INT
SET @Months = DATEDIFF(MM,@FROMDATE,@TODATE)
IF (DATEPART(MM,@FromDate) <= (DATEPART(MM,@TODATE))+1)
BEGIN
SELECT CAST(DATEDIFF(YY,@FROMDATE,@TODATE) AS VARCHAR(5)) + ' Years '+ CAST( (DATEPART(MM,@TODATE)-DATEPART(MM,@FROMDATE)) AS VARCHAR(5))+1 +' Month'
END
ELSE
BEGIN
SELECT CAST(DATEDIFF(YY,@FROMDATE,@TODATE)-1 AS VARCHAR(5)) +' Years '+ CAST(12-(DATEPART(MM,@FROMDATE)) + DATEPART(MM,@TODATE)+1 AS VARCHAR(5) ) +' Month'
END
于 2016-10-21T10:49:52.857 回答
0
创建 FUNCTION [dbo].[fn_getEmployePeriod] (@dateofbirth DATETIME) 返回 VARCHAR(100) 开始声明 @currentdatetime DATETIME；声明@years INT；声明@months INT；声明@days INT；声明@currentMonthdays INT；声明@result VARCHAR(100); SET @currentdatetime = GETDATE();--当前日期时间
IF ( @dateofbirth <= GETDATE() )
BEGIN
SELECT @years = DATEDIFF(YEAR, @dateofbirth, @currentdatetime); -- To find Years
SELECT @months = DATEDIFF(MONTH, @dateofbirth,
@currentdatetime) - ( DATEDIFF(YEAR,
@dateofbirth,
@currentdatetime)
* 12 );
SELECT @days = DATEPART(d, @currentdatetime) - DATEPART(d,
@dateofbirth);-- To Find Days
SELECT @currentMonthdays = ( SELECT DAY(DATEADD(DD, -1,
DATEADD(mm,
DATEDIFF(mm, 0,
GETDATE()), 0)))
);
IF ( @months < 0 )
BEGIN
SET @months = 12 + @months;
SET @years = @years - 1;
END;
IF ( @days < 0 )
BEGIN
SET @days = @currentMonthdays + @days;
IF(@months<>0)
begin
SET @months = @months - 1;
END
ELSE
BEGIN
SET @years = @years - 1;
SET @months = 11;
end
END;
-- 查找月份
SET @result = CAST(@years AS VARCHAR(3)) + ' years, '
+ CAST(@months AS VARCHAR(3)) + ' months, '
+ CAST(@days AS VARCHAR(3)) + ' days';
END;
ELSE
BEGIN
SET @result = 'Invaild date of birth';
END;
RETURN @result;
END;
于 2019-01-06T05:31:13.907 回答
-1
SELECT convert(varchar(3),DATEDIFF(MONTH, '2015-01-01', GETDATE())/12) +' years '+
convert(varchar(2),DATEDIFF(DD, '2016-09-21', GETDATE()) % 12)+ ' months'
AS EXPERIENCE
于 2016-09-26T10:38:11.620 回答