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我正在尝试在这里做一个配对游戏，我几乎完成了。给出 userInput 后​​，我​​试图用隐藏的值替换游戏板。我已经编写了代码来查看“A1”是否可以工作，但它不会。有人对如何用另一个元素替换数组的元素有任何想法吗？还是我做错了？

import java.util.*;
public class breitje_MatchUp{
   static Scanner input = new Scanner(System.in);
   static int i=0, count=0;
   static char[][] clearBoard = new char[4][4];
   static char[][] board = new char[4][4];
   public static void main(String[] args){
      gamePlay();

   }

   public static void drawMenu(){
      System.out.println("Welcome to the Match Up game! \n");  
      System.out.println("Please select from the following: ");  
      System.out.println("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~");  
      System.out.println("1. New Game");  
      System.out.println("2. Quit");  
      System.out.println("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~");  
      int optionSelect = input.nextInt();
      System.out.println("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~");  
      while(optionSelect!=1 && optionSelect !=2){
         System.out.println("Please enter 1 (New Game) or 2(Quit)");
         optionSelect = input.nextInt();}
      if (optionSelect == 1)
         System.out.print("START GAME HERE********");
      else if (optionSelect == 2)
         System.out.println("Thanks for playing! Have a great day.");  
   }


   public static char[][] buildBoard(){
      char[][] board = new char[4][4];
      for(int i = 0; i <board.length; i ++){
         for(int j = 0; j<board[0].length;j++){
            board[i][j]=(char)(65+Math.random()*8);
         }
      }
      return board;
   } 

   public static void drawBoard(){
      for(int row1 = 0; row1 < 4; row1++) {
         // this will create a new line for each new row
         System.out.println("");
         for(int col1 = 0; col1 < 4; col1++) {
            // this will print out the 4 row variable values
            clearBoard[row1][col1]='.';
         }        
      }
      System.out.format("   %2s %2s %2s %2s \n",'A','B','C','D');
      System.out.format("   %2s %2s %2s %2s \n",'-','-','-','-');
      System.out.format("1 |%2s %2s %2s %2s \n",
          clearBoard[0][0],
          clearBoard[0][1],
          clearBoard[0][2],
          clearBoard[0][3]);
      System.out.format("2 |%2s %2s %2s %2s \n",
          clearBoard[1][0],
          clearBoard[1][1],
          clearBoard[1][2],
          clearBoard[1][3]);
      System.out.format("3 |%2s %2s %2s %2s \n",
          clearBoard[2][0],
          clearBoard[2][1],
          clearBoard[2][2],
          clearBoard[2][3]);
      System.out.format("4 |%2s %2s %2s %2s \n",
          clearBoard[3][0],
          clearBoard[3][1],
          clearBoard[3][2],
          clearBoard[3][3]);  
   } 


   public static void gamePlay(){
      while(!checkForWin(count)){
         drawBoard();
         System.out.print("Card 1: Column/Row (Ex: A3) : "); //input 1
         String userInput = input.nextLine(); System.out.println();
         userInput = userInput.toUpperCase().trim();

         convertInput(userInput);

         drawBoard();

         System.out.print("Card 2: Column/Row (Ex: A3) : "); //input 2
         String userInput1 = input.nextLine(); System.out.println();
         userInput1 = userInput.toUpperCase().trim();
      }
      drawMenu();
   }
   public static void convertInput(String input){
      if(input.equals("A1"))
         clearBoard[0][0]=board[0][1];

   }

   public static boolean checkForWin(int count){
      if (count == 8)
         return true;
      else
         return false;
   }
}
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3 回答 3

1

您所做的更改将被 draw 方法覆盖。

        clearBoard[row1][col1]='.'; // this will print out the 4 row variable values

我不清楚你想用这种方法完成什么，因为评论完全不同意代码 - 你将值设置为一个句点，而不是在该行打印任何内容。

这里还有很多风格需要改进——一个名为的方法draw不应该有重置板的副作用。

于 2012-11-27T06:27:39.230 回答
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除了@I82Much 的回答之外，您还声明了 buildBoard 方法但从不调用它，因此当您设置 clearBoard[0][0]=board[0][1] 时，您将其设置为 null（我认为）。

在您的 buildBoard 方法中，您重新声明了一个新的板数组，该数组在范围内是本地的。

于 2012-11-27T06:36:24.793 回答
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查看 JAVA 的 Arrays API；它几乎没有非常有趣和有用的方法。 http://docs.oracle.com/javase/6/docs/api/java/util/Arrays.html

于 2012-11-27T06:39:50.670 回答