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简单的程序:2 个按钮(上一个/下一个)和一个显示文本的文本视图。

我有意创建了一个索引(在方法内)

private void index(){
    Intent i = new Intent(this, Index.class);
    startActivityForResult(i, 1);
}

Index.class(带有 3 个按钮):

button1.setOnClickListener(new View.OnClickListener() {
    public void onClick(View v) {   
        String result = "1";
        Intent returnIntent = new Intent();
        returnIntent.putExtra("result",result);
        setResult(RESULT_OK,returnIntent);     
        finish();
    }
});

主类

String value = "1";
final String prog1[] = new String[16];
final String prog2[] = new String[105];
final String prog3[] = new String[66];

int a;
int b;
int c=3;

int array1start = 0; int array1end = 15;
int array2start = 0; int array2end = 105;
int array3start = 0; int array3end = 65;



@Override
public void onCreate(Bundle savedInstanceState){ 
  super.onCreate(savedInstanceState);


if (value.equals("1")){

        a = array1start;
        b = array1end;
        prog=prog1; 

    }
    else if (value.equals("2")){
        a = array2start;
        b = array2end;
        prog=prog2; 

textView1.setText(""+prog[a]);

protected void onActivityResult(int requestCode, int resultCode, Intent data) {

    if (requestCode == 1) {

         if(resultCode == RESULT_OK){

          String result=data.getStringExtra("result");
          value=result;
          Toast toast2=Toast.makeText(this,"value: "+value,Toast.LENGTH_LONG);
          toast2.show();
    }

    if (resultCode == RESULT_CANCELED) {
         //Write your code on no result return 

    }}
    }//onAcrivityResult

此时,索引类中的选择应该是在主类中将结果字符串更改为“值”字符串

private void index(){


    Intent i = new Intent(this, Index.class);
    startActivityForResult(i, 1);



}

我的 textview 通过索引类从 array1 或 array2 获取数据

所以,我不明白如何更新 textview(因为索引值是正确的)。

谢谢您的帮助

4

1 回答 1

1

将您的代码放入函数中onActivityResult

if (value.equals("1")){

        a = array1start;
        b = array1end;
        prog=prog1; 

    }
    else if (value.equals("2")){
        a = array2start;
        b = array2end;
        prog=prog2; 

textView1.setText(""+prog[a]);
于 2012-11-26T13:03:51.763 回答