1

我难住了。为什么查询可以在 phpMyAdmin 中工作，但不能在 MAMP 环境中工作？我已经回显了该查询，该查询在 MAMP 中返回了 0 个结果，将其复制并粘贴到 phpMyAdmin 中，并且相同的查询返回了预期的结果。

select
   c.id
from
    (select id, business_id 
     from coup 
     where match(name) against ('$search')
    ) as c
    left join
       (select business_id 
        from bus 
        where match(name, category, subcat) against ('$search')
       ) as b on
        c.business_id = b.business_id 
    inner join bloc z on
        c.business_id = z.business_id
where
    z.zip = '$zip'

以下是代码中出现的行

$q = "select c.id from (select id, business_id from ".TBL_COUPONS." where match(name) against ('".$search."')) as c left join (select business_id from ".TBL_BUSINESS." where match(name, category, subcat) against ('".$search."')) as b on c.business_id = b.business_id inner join ".TBL_BLOCATION." as l on c.business_id = l.business_id where l.zip = '".$zip."'";
$rs = mysql_query($q) or die(mysql_error());
$rec = array();
while(($row = mysql_fetch_array($rs)) !== FALSE ){
    $rec[] = $row[0];   
}

echo $q 显示：

select c.id from (select id, business_id from coupons where match(name) against ('walk')) as c left join (select business_id from business where match(name, category, subcat) against ('walk')) as b on c.business_id = b.business_id inner join buslocations as l on c.business_id = l.business_id where l.zip = '91326'
4

1 回答 1

2

根据我的经验，问题有 80% 可能是您使用了两个包含不同数据的不同数据库。

您应该将查询分解为更简单的测试，直到您能找出不同之处。

在两种环境中尝试以下查询：

SELECT COUNT(*) FROM coupons;
SELECT COUNT(*) FROM coupons WHERE MATCH(name) AGAINST ('walk');

SELECT COUNT(*) FROM business;
SELECT COUNT(*) FROM business WHERE MATCH(name, category, subcat) AGAINST ('walk');

SELECT COUNT(*) FROM bloc;
SELECT COUNT(*) FROM bloc WHERE zip = '91326';

这些查询中的一个或多个的结果可能会有所不同。这意味着您有两个具有不同数据的不同数据库。同一个 MySQL 实例上的两个模式，或者两个单独的 MySQL 实例。您没有连接到您认为在一个或另一个界面中连接的数据库。

于 2009-08-31T06:05:11.427 回答