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一个用于访问，一个用于取货，当用户将访问或取货之一添加到列表中时，它也会添加到列表框中以向用户显示。

我的问题是，当我单击列表框中的项目时，例如 Indexchanged，我希望它打开与访问或交付相关的新 GUI，因此，如果他们单击访问，它会打开访问表单，如下所示代码，但我怎样才能让它区分列表，以便它知道要打开哪种形式？

 private void lstVisits_SelectedIndexChanged(object sender, EventArgs e)
    {
        //Allow the user to click on the listbox to open a visit
        //This event is called after the user has clicked on the list
        int index = lstVisits.SelectedIndex;
        //Get the index of the Visit that the user has clicked upon

        Visits selected = theList.getVisits(index);
        //Get the visits object from the list

        Visitsform.visits = selected;
        //Ensure that the appointment form references the selected visit

        Visitsform.ShowDialog();
        //Show the visits form

        updateList();
        //update the list as the user may have deleted the appointment
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1 回答 1

1

如果两个列表中的项目都存储在同一个列表框中，那么您可以使用如下内容：

编辑：如果要从列表框中获取对象，则应将它们作为对象添加到列表框中，例如：

Visits v = new Visit();
Pickups p = new Pickup();
lstVisits.Items.Add(v);
lstVisits.Items.Add(p);    


private void lstVisits_SelectedIndexChanged(object sender, EventArgs e)
            {
                if (listBox1.SelectedItems.Count > 0)
                {
                    object o = listBox1.SelectedItems[0];
                    if (o is Visits)
                    {
                        Visits visit = (Visits)o;
                        Visitsform.visits = visit;
                        Visitsform.ShowDialog();
                    }
                    else
                    {
                        Deliveries delivery = (Deliveries)o;
                        Deliveriesform.visits = visit;
                        Deliveriesform.ShowDialog();
                    }
                }
            }
于 2012-11-25T18:23:44.177 回答