php - 如何使用 PHP 从 HTML 代码块中删除标签？

Question

我只想从 html 中删除特定 URL 中的图像

例如： http: //pastebin.com/Qaw4dRbT

<p>Lorem ipsum dolor sit amet, consectetuer adipiscing elit. Aenean commodo ligula eget dolor. Aenean massa. Cum sociis natoque penatibus et magnis dis parturient montes, nascetur ridiculus mus.<img src="http://www.another-domain.tld/r/151230695794/32310/s/25e829c1/removeit.img" alt="" width="1" height="1" border="0" /></p>

我想从 another-domain.tld 中删除图像并保留另一个图像。

谢谢

Answer 1

使用 xpath 查找它并将其从其父级中删除：

// Build a new DOMDocument, load it up with your HTML
$doc = new DOMDocument();
$doc->loadHTML($html);

// Reference to our DIV container
$container = $doc->getElementsByTagName("div")->item(0);

// New instance of XPath class based on $doc
$xpath = new DOMXPath($doc);

// Get images that contain 'specific-domain.tld' in their src attribute
$images = $xpath->query("//img[contains(@src,'specific-domain.tld')]");

// For every image found
foreach ($images as $image) {
    // Remove that image from its parent
    $image->parentNode->removeChild($image);
}

// Output the resulting HTML of our container
echo $doc->saveHTML($container);

可执行演示：http ://sandbox.onlinephpfunctions.com/code...6529d025e135013184e