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有人建议我再问一次这个问题,但要更深入。

这是我的脚本:

    <?php
    //Loggedin
    if($_SESSION['login']!=1)
    {
        print "You must be logged in.";
        include($root . 'footer.php');
        exit;
    }
    //Check banned account
    elseif($ui['level']=="2"){
        print "Sorry but your account is banned.";
        include($root . 'footer.php');
        exit;
    }
    //Check email verified
    elseif($ui['email_check']=="0"){
        print "Sorry but your account has not been verified, to verify your account now please visit <a href='index.php?index=verify&email=".$ui['email']."'>THIS LINK</a>.";
        include($root . 'footer.php');
        exit;
    }
date_default_timezone_set('America/New_York');
$country= $ui['country'];
$dates=mysql_query("SELECT * FROM `contest` WHERE `countries` LIKE '%$country%'");
$timestamp = time();

    $getcontests = $os_DB->query("SELECT * FROM contest WHERE date_1 <= '$timestamp' AND date_2 >= '$timestamp' AND countries LIKE '%$country%'");
        $num = $os_DB->num($getcontests);

            if($num == 0){
            print"<td colspan='4'>There are currently no active contests</td>";
            }
            else
            {

    while ($dat = mysql_fetch_array($dates)) {
        $tname = preg_replace('/\s+/', '', $dat['name']);
        $places="(SELECT * FROM `".$tname."_contest` WHERE `username` <> 'cassa' ORDER BY `completed` DESC LIMIT ".$dat['rewards'].")";
        $results=mysql_query($places) or die(mysql_error());




        $reward = array("".$dat['reward_1'].",".$dat['reward_2'].",".$dat['reward_3'].",".$dat['reward_4'].",".$dat['reward_5'].",".$dat['reward_6'].",".$dat['reward_7'].",".$dat['reward_8'].",".$dat['reward_9'].",".$dat['reward_10']."");

        $rewards = implode(",", $reward);

        $rewardsa = explode(",", $rewards);
        $i=0;
        $a=1;

            // Offers Contest

        if(time() <= $dat['date_2'] && time() >= $dat['date_1'] && $dat['type'] == offer) {
            print" <table width ='100%'><tr><th align='center'><font size='4'>{$dat['name']}</font></th><th align='right'><font size='1'>".date("m/d/Y h:i A", $dat['date_1'])."-".date("m/d/Y h:i A", $dat['date_2'])."</font></th></tr></table><br />".$dat['desc']."<br /><font size='1' color='white'>You must complete offers worth at least ".$dat['min_points']." points or $".$dat['min_cash']." to count towards contest!<br /><br />
            You must also complete at least ".$dat['min_offers']." offers in order to be eligible for winnings.</font><br /><br />";
            print" <table width ='100%'><tr><th align='left'>Place</th><th align='center'>User</th><th align='right'>Prize</th><th align='right'>Completed</th></tr>";

        if(mysql_num_rows($results) == 0){
            foreach($rewardsa as $rewa){
                if(!empty($rewa['$i'])){
                    if($dat['r_type'] == points){
                        print"  <tr><td align='left'>{$a}</td><td align='center'>......</td><td align='right'>{$rewardsa[$i]} points</td><td align='right'>--</td></tr>";
                    }
                if($dat['r_type'] == cash){
                    print"  <tr><td align='left'>{$a}</td><td align='center'>......</td><td align='right'>$".$rewardsa[$i]."</td><td align='right'>--</td></tr>";
                }
            $i++;
            $a++;
                }
            }
        }


    while ($place = mysql_fetch_array($results)) {
        if($dat['r_type'] == points){
            print"  <tr><td align='left'>{$a}</td><td align='center'>{$place['username']}</td><td align='right'>{$rewardsa[$i]} points</td><td align='right'>{$place['completed']}</td></tr>";
        }
        if($dat['r_type'] == cash){
            print"  <tr><td align='left'>{$a}</td><td align='center'>{$place['username']}</td><td align='right'>$".$rewardsa[$i]."</td><td align='right'>{$place['completed']}</td></tr>";
        }
        $i++;
        $a++;

    }
    ///Line I am working with///
    $getyou= mysql_query("SELECT COUNT(*) AS Place, t.*
    FROM ".$tname."_contest t
    GROUP BY t.id
    HAVING Place <= 3 OR username = '".$ui['username']."'");
        $youu = mysql_fetch_array($getyou);
        print"  <tr><td align='left'>{$youu['Place']}</td><td align='center'>You</td><td align='right'>---</td><td align='right'>{$youu['completed']}</td></tr>";
        }
    }
        }

?>  
        </table>

使用这个脚本,我希望能够向登录的用户显示他们当前在当前获胜者下的比赛中所处的位置。

这就是我希望桌子的样子。

-----------------------------------------
| Place |    User   | Prize | Completed |
|   1   | Someuser1 | $5.00 |     5     |
|   2   | Someuser2 | $2.50 |     3     |
|   3   | Someuser3 | $1.25 |     2     |
|   20  |    You    |  ---  |     1     |
-----------------------------------------

这是它的样子

-----------------------------------------
| Place |    User   | Prize | Completed |
|   1   | Someuser1 | $5.00 |     5     |
|   2   | Someuser2 | $2.50 |     3     |
|   3   | Someuser3 | $1.25 |     2     |
|   1   |    You    |  ---  |     1     |
-----------------------------------------

这是我的表结构。

    Column   |  Type | Null |  Default
--------------------------------------
    id       |int(11)|  No  |   
    username |text   |  No  |   
    completed|int(11)|  No  |   

正如您所看到的,所有这些都来自一个表,并且该位置不是由数据库定义的,而是由脚本本身定义的。

希望这可以比我上一个问题更清楚。

编辑:使用肖恩的代码,这就是我得到的。

-----------------------------------------
| Place |    User    | Prize | Completed |
|   1   |   kikkat   | $5.00 |     1     |
|   2   |xXchris744Xx| $2.50 |     1     |
|   3   |  kira423   | $1.25 |     1     | /// This line is me
|   7   |    You     |  ---  |     1     | /// But it shows my current place as 7
-----------------------------------------
4

1 回答 1

1

这可以通过嵌套查询来完成 -

$getyou= mysql_query("SELECT 
                        (SELECT count(*)+1 AS rank FROM contest WHERE completed >
                          (SELECT completed FROM contest WHERE username = '".$ui['username']."' ORDER BY completed DESC LIMIT 1)) as Place,
                        c.* FROM contest c WHERE username = '".$ui['username']."'");
$youu = mysql_fetch_array($getyou);
    print"  <tr><td align='left'>{$youu['Place']}</td><td align='center'>You</td><td align='right'>---</td><td align='right'>{$youu['completed']}</td></tr>";

这是查询从内到外的工作方式-

第一个(内部)SELECT获得completed金额username =$ui['username']

SELECT completed FROM contest WHERE username = '".$ui['username']."' ORDER BY completed DESC LIMIT 1

第二个(中间)SELECT使用该completed数量并执行count所有已完成的行中的 a ,添加 a 1count并将其保存为 users Place

SELECT count(*)+1 AS rank FROM contest WHERE completed > '#' // # represents the `completed` amount for the `$ui['username']` that we got in the 1st SELECT

第三个/最后一个(外部)SELECT现在只获取行数据username =$ui['username']

SELECT Place, c.* FROM contest c WHERE username = '".$ui['username']."'  // Place was created/defined in early SELECTS, now we just get the rest of the data using c.*

编辑

tiebreaker要在一个或多个具有相同数字时添加 a completed,您还需要按 the 对查询进行排序id。因此,将您的第一个查询更改为 -

$places="(SELECT * FROM `".$tname."_contest` WHERE `username` <> 'cassa' ORDER BY `completed`,`id` DESC LIMIT ".$dat['rewards'].")";
                                                                                              ---

ORDER BY id并将and添加>=到第二个查询

$getyou= mysql_query("SELECT 
                        (SELECT count(*)+1 AS rank FROM contest WHERE completed >=
                                                                                --
                          (SELECT completed FROM contest WHERE username = '".$ui['username']."' ORDER BY completed DESC LIMIT 1) ORDER BY `completed`,`id`) as Place,
                                                                                                                                 -------------------------
                        c.* FROM contest c WHERE username = '".$ui['username']."'");

编辑 #2 试试这个新查询。前一个不是选择确切的行,而是选择最后一行tied

$getyou= mysql_query("SELECT Place, c.* FROM
                      (SELECT @Place:=@Place+1 AS Place, c.*
                        FROM contest c, (SELECT @Place := 0) r ORDER BY completed DESC, id ASC ) c
                         WHERE username = '".$ui['username']."'");

这个新查询创建了一个临时的新列Place,使用SELECT @Place := 0,然后我们使用 'Place' 获取用户@Place:=@Place+1 AS Place

于 2012-11-25T04:50:35.823 回答