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我有一个带有二维数组的程序。首先我像这样分配数组：

char **crossword;
crossword = (char **) malloc(n* sizeof(*crossword));
for (i = 0; i < n; i++)
    crossword[i] = (char *)malloc(n);

其中 n = 50。

然后我有函数，从标准输入读取字符串。问题是，我不知道这些字符串会有多少或多长。

void read(char **p,int *n)
{
char tmp = 0,prevtmp = 0;
int i = 0, j = 0,x;

while (1)
{
    prevtmp = tmp;
    tmp = getchar();
    if ((tmp == '\n' && prevtmp == '\n') || feof (stdin))
    {
        *n = i;
        break;
    }
    if (tmp == '\n')
    {
        p[i][j] = '\0';
        i++;
        if (i == *n)
        {
            p = (char **) realloc(p, 2*i); // if there is more strings than space for them, allocate more memory.
            for (x = i; x < 2*i; x++)
                p[x] = (char *) malloc (*n);

            *n *= 2;
        }
        j = 0;
        continue;
    }
    p[i][j] = tmp;
    j++;
    if (j == *n)
        p[i] = (char *)realloc(p[i], 2*j); //same as above
}
}

函数是这样调用的：

read(crossword,&n);

当不需要 realloc（少于 50 个字符串，每个小于 50 个字符）时，此函数工作正常。但是对于大量输入，这会失败

*** glibc detected *** ./a.out: malloc(): memory corruption (fast): 0x00000000014282f0 *** error.

我认为我的问题在于我重新分配更多内存的部分，这是 valgrind 的输出：

==8885== Invalid write of size 1
==8885==    at 0x40084C: read (in /home/xerw/Dropbox/CVUT/PROGTEST/du6/a.out)
==8885==    by 0x40177F: main (in /home/xerw/Dropbox/CVUT/PROGTEST/du6/a.out)
==8885==  Address 0x51f2b88 is not stack'd, malloc'd or (recently) free'd
==8885== 
==8885== Invalid write of size 8
==8885==    at 0x4008A6: read (in /home/xerw/Dropbox/CVUT/PROGTEST/du6/a.out)
==8885==    by 0x40177F: main (in /home/xerw/Dropbox/CVUT/PROGTEST/du6/a.out)
==8885==  Address 0x51f4f00 is not stack'd, malloc'd or (recently) free'd

valgrind: m_mallocfree.c:266 (mk_plain_bszB): Assertion 'bszB != 0' failed.
valgrind: This is probably caused by your program erroneously writing past the
end of a heap block and corrupting heap metadata.  If you fix any
invalid writes reported by Memcheck, this assertion failure will
probably go away.  Please try that before reporting this as a bug.

==8885==    at 0x3804C6CF: ??? (in /usr/lib/valgrind/memcheck-amd64-linux)
==8885==    by 0x3804C812: ??? (in /usr/lib/valgrind/memcheck-amd64-linux)
==8885==    by 0x38000883: ??? (in /usr/lib/valgrind/memcheck-amd64-linux)
==8885==    by 0x380574EA: ??? (in /usr/lib/valgrind/memcheck-amd64-linux)
==8885==    by 0x38057E03: ??? (in /usr/lib/valgrind/memcheck-amd64-linux)
==8885==    by 0x380212DC: ??? (in /usr/lib/valgrind/memcheck-amd64-linux)
==8885==    by 0x3802146A: ??? (in /usr/lib/valgrind/memcheck-amd64-linux)
==8885==    by 0x3808F656: ??? (in /usr/lib/valgrind/memcheck-amd64-linux)
==8885==    by 0x3809E68C: ??? (in /usr/lib/valgrind/memcheck-amd64-linux)

sched status:
  running_tid=1

Thread 1: status = VgTs_Runnable
==8885==    at 0x4C2B3F8: malloc (in /usr/lib/valgrind/vgpreload_memcheck-amd64-linux.so)
==8885==    by 0x4008A5: read (in /home/xerw/Dropbox/CVUT/PROGTEST/du6/a.out)
==8885==    by 0x40177F: main (in /home/xerw/Dropbox/CVUT/PROGTEST/du6/a.out)

我一直在试验指针很短的时间，所以我不知道出了什么问题。我一直试图解决这个问题几个小时，但我没有想出任何东西。

我究竟做错了什么？

4

1 回答 1

1

问题似乎与以下行有关：

p = (char **) realloc(p, 2*i);

我想应该是：

p = (char **) realloc(p, (2*i)*sizeof(char*));

即你想增加数组来保存元素，2*i所以你需要分配2*i.char*

于 2012-11-24T20:58:19.163 回答