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在我的二十一点计划中，我有：

Card c = dealCard(deck); //deals the card
updatePoints(players[i], c); // calls updatePoints below.

updatePoints 函数如下所示：

public static void updatePoints(Player player,  Card c){

        int point = c.getValue();
        if(player.getPoints() + point >21 && (player.ace1 == 11 || player.ace2 == 11 || player.ace3 == 11 || player.ace4 == 11)){
            player.points -= 10;
            player.setPoints(point);
            if (player.ace1 == 11){
                player.ace1 = 1;
            }else if(player.ace2 == 11){
                player.ace2 = 1;
            }else if(player.ace3 == 11){
                player.ace3 = 1;
            }else if (player.ace4 == 11){
                player.ace4 = 1;
            }
        }
        if (point == 1){
            //default value for player.ace1 .. player.ace4 is 0


            if(player.ace1 == 0){
                player.ace1 = 11;
                player.setPoints(11);
            }else if (player.ace2 == 0){
                player.ace2 = 11;
                player.setPoints(11);
            }else if (player.ace3 == 0){
                player.ace3 = 11;
                player.setPoints(11);
            }else if(player.ace4 == 0){
                player.ace4 = 11;
                player.setPoints(11);
            }

        }else{
            player.setPoints(point);
        }
        return;
    }

由于某种原因，当点数超过 21 时，这不会改变 ace 值，也不会调整 ace。任何帮助将不胜感激。谢谢

4

1 回答 1

2

您的代码似乎太复杂了。无需为每个 ace 设置一个变量，只需计算您尚未减少到 a 的 ace 数量1：

private int fullAceCount;

更新假设11为王牌，但也更新王牌计数：

if (points == 11) { // if it's an ace
    fullAceCount++; // save it for later deduction
}

然后在更新任何卡后，检查是否需要扣除10

if (total > 21 && fullAceCount > 0) {
    total =- 10;
    fullAceCount--; // record that you've used up one of your aces
}

你就完成了。

于 2012-11-24T17:42:32.867 回答