0

我有两个实体：第一人（表人）；

@Entity
public class Person implements Serializable {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", nullable = false)
    private Integer id;
    @Column(name = "name", nullable = false, length = 2147483647)
    private String name;
    @Column(name = "first_name", nullable = false, length = 2147483647)
    private String firstName;
    @OneToMany(cascade = CascadeType.ALL, mappedBy = "peopleId")
    private List<PeopleEmail> peopleEmailList;

    //... constuctors
    //... getters setters
}

和类 PeopleEmail

@Entity
public class PeopleEmail implements Serializable {
    private static final long serialVersionUID = 1L;
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "id", nullable = false)
    private Integer id;
    @NotNull
    @Column(name = "email", nullable = false, length = 2147483647)
    private String email;
    @JoinColumn(name = "people_id", referencedColumnName = "id", nullable = false)
    @ManyToOne(optional = false)
    private Person peopleId;

    //... constuctors
    //... getters setters
}

如您所见，两个实体都处于一对多关系中。我想创建另一个类：

public class PersonAndCompany{
   private String personName;
   private String companyName;
   private int emailCount;

    //... constuctors
    //... getters setters
}

我想编写 typequery 来填充 PersonAndCompany.class 字段，其中包含人名和 companyName（另一个类）和电子邮件计数，其中人员电子邮件计数超过 2。我想使用标准 api。我写了一些代码，但我不知道如何在 PersonAndCompany.class 中添加条件并填写 emailcount。

CriteriaBuilder cb = em.getCriteriaBuilder();
CriteriaQuery<PersonAndCompany> cq = cb.createQuery(PersonAndCompany.class);
Root<Person> person = cq.from(Person.class);
Join<Person, Company> company = person.join(Person_.companyId);
cq.where(cb.greaterThan(cb.size(person.get(Person_.peopleEmailList)), 2));

Selection<PersonAndCompany> select = cb.construct(PersonAndCompany.class,
                        person.get(Person_.firstName),
                        company.get(Company_.name));
cq.select(select);
TypedQuery<PersonAndCompany> query = em.createQuery(cq);
return query.getResultList();
4

2 回答 2

1

我认为可以在某些 JPA 提供和某些数据库的 select 子句中包含一个子查询。

Select p.firstName, c.name, (select count(e) from Email e where e.person = p) from Peron p join p.company c where size(p.emails) > 2

否则，您将需要使用计数和某种分组依据。然后可以将您在 where 子句中的大小检查移到 have 子句中。

在 JPQL 中，它类似于，Criteria 将是等价的，

Select p.id, p.firstName, c.name, count(e) from Peron p join p.company c join p.peopleEmaiList e group by p.id, p.firstName, c.name having count(e) > 2

您也可以随时读取对象，然后在 Java 中获取集合的 size() 。您可以对电子邮件和公司使用连接或批量提取来避免 n+1 查询。

于 2012-11-26T14:23:04.543 回答
0

当我想将派生值或计算值 ion 转换为不同的结构时，我对 TupleQueries 有更多的运气，如下所示：

CriteriaBuilder cb = getEntityManager().getCriteriaBuilder();
CriteriaQuery<Tuple> cq = cb.createTupleQuery(); 
// add cq.from and joins 
// add cq.where predicates 
cq.select( cb.tuple(   
  person.get(Person_.firstName).alias("person"),  
  company.get(Company_.name).alias("company"),  
  // and maybe ...
  cb.size(person.get(Person_.peopleEmailList)).alias("emailcount") );
// ...
...
TypedQuery<Tuple> typedQuery = getEntityManager().createQuery(cq);
for(Tuple t : typedQuery.getResultList()) {
  PersonAndCompany ret = new PersonAndCompany();
  ret.setPersonName( t.get("person", String.class) );
  ret.setCompanyName( t.get("company", String.class) );
  ret.setEmailCount( t.get("emailcount", Integer.class) );
}
return ret;

希望有帮助。祝你好运 ;）

于 2014-07-16T13:15:28.163 回答