python - 我想生成连续的日期

Question

我有这样的代码：

import time
from datetime import date
startyear = raw_input("start year: ")
startmonth = raw_input("start month: ")
startday = raw_input("start day: ")
endyear = raw_input("end year: ")
endmonth = raw_input("end month: ")
endday = raw_input("end day: ")

startdate = date(int(startyear), int(startmonth), int(startday))
while startdate < date(int(endyear), int(endmonth), int(endday)):
    print startdate
    startdate = startdate.replace(day=startdate.day + 1)

这段代码的作用是：
1.通过手动输入
获取开始和结束日期 2.生成它们之间的日期列表

但问题是，如果我设置日期，例如，
startdate: 2012-10-28
enddate: 2012-11-4
输出将是：

2012-10-28
2012-10-29
2012-10-30
2012-10-31
ValueError: day is out of range for month

我希望输出如下：

2012-10-28
2012-10-29
2012-10-30
2012-10-31
2012-11-01
2012-11-02
2012-11-03
2012-11-04

所以我希望日期通过月份。有什么建议么？任何帮助都会非常棒。

Answer 1

而不是startdate.replace()，您应该使用timedelta...

from datetime import date, timedelta
# Get input here...
while startdate < date(int(endyear), int(endmonth), int(endday)):
    print startdate
    startdate += timedelta(days=1)

Answer 2

有一个名为python-dateutil的模块对这类事情非常有用：

from datetime import datetime
from dateutil.rrule import rrule, DAILY

list(rrule(DAILY, dtstart=datetime(2012, 11, 24), until=datetime(2012,11,30)))
# [datetime.datetime(2012, 11, 24, 0, 0), datetime.datetime(2012, 11, 25, 0, 0), datetime.datetime(2012, 11, 26, 0, 0), datetime.datetime(2012, 11, 27, 0, 0), datetime.datetime(2012, 11, 28, 0, 0), datetime.datetime(2012, 11, 29, 0, 0), datetime.datetime(2012, 11, 30, 0, 0)]

并且有其他选项，例如，按星期几（仅适用于工作周的 MO、TU、WE、TH、FR）：

from dateutil.rrule import MO, WE
list(rrule(DAILY, byweekday=[MO, WE], dtstart=datetime(2012, 11, 24), until=datetime(2012,11,30))
# [datetime.datetime(2012, 11, 26, 0, 0), datetime.datetime(2012, 11, 28, 0, 0)]