2

我有这个代码,它结合了两个列表:

let rec union list1 list2 =
    match list2 with
    | [] -> list1
    | x::xs when mem x list1 -> union list1 xs
    | x::xs -> x::(union list1 xs)

但是,这并没有给我想要的结果;我希望结果按照最小的顺序排列。我该怎么做呢?

4

2 回答 2

2

如果这两个参数已经排序,那么您可以遍历它们并在结果中添加更小的元素:

let rec union list1 list2 =
    match list1, list2 with
    | [], other | other, [] -> other
    | x::xs, y::ys when x < y -> x :: (union xs list2)
    | x::xs, y::ys -> y :: (union list1 ys)
于 2012-11-23T13:59:56.150 回答
0

即使您的输入未排序,这也将起作用:

let sortedUnion list1 list2 =
    let rec union list1 list2 =
        match list2 with
        | [] -> list1
        | x::xs when mem x list1 -> union list1 xs
        | x::xs -> x::(union list1 xs)
    let unsorted = union list1 list2
    List.sort unsorted
于 2012-11-23T14:01:25.973 回答