0

我有一个 Web 服务，它需要一个 SOAP 请求来对 String 执行一个简单的方法。现在我在 Android 上编写了应用程序来使用这个 Web 服务，我希望它序列化一些数据并通过 SOAP 将其发送到 Web 服务。

这是一些代码：

public class SendedLocation implements Serializable {
    public String MESSAGE;

    public SendedLocation() {
    }

    public SendedLocation(int mId, float mLongitude, float mLatitude) {

        MESSAGE = String.valueOf(mId) + ";" + String.valueOf(mLongitude) + ";" +  String.valueOf(mLatitude);
    }

    public Object getProperty(int arg0) {

        switch (arg0) {
        case 0:
            return MESSAGE;
        }

        return null;
    }

    public int getPropertyCount() {
        return 1;
    }

    public void getPropertyInfo(int index, Hashtable arg1, PropertyInfo info) {
        switch (index) {
        case 0:
            info.type = PropertyInfo.STRING_CLASS;
            info.name = "MESSAGE";
            break;
        default:
            break;
        }
    }

    public void setProperty(int index, Object value) {
        switch (index) {
        case 0:
            MESSAGE = value.toString();
            break;
        default:
            break;
        }
    }

}

public void callWebService(int ID, float Longitude, float Latitude) {
    try {
        SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
        AndroidHttpTransport androidHttpTransport = new AndroidHttpTransport(
                URL);

        SendedLocation mSended = new SendedLocation(ID, Longitude, Latitude);

        PropertyInfo p1 = new PropertyInfo();
        p1.setName("mSended");
        p1.setValue(mSended);
        p1.setType(mSended.getClass());
        request.addProperty(p1);

        SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
                SoapEnvelope.VER11);

        envelope.dotNet = true;
        envelope.setOutputSoapObject(request);

        envelope.addMapping(NAMESPACE, "mSended", mSended.getClass());

        MarshalString marshalString = new MarshalString();

        marshalString.register(envelope);

        // Make the soap call.
        androidHttpTransport.call(SOAP_ACTION, envelope);

        Object results = (Object) envelope.getResponse();
        // to get the data String
        // resultData=result.getProperty(0).toString();
        String temp = results.toString();
        System.out.println(temp);
    } catch (Exception aE) {
        System.out.println(aE.toString());
    }
}
public class MarshalString implements Marshal 
{


    public Object readInstance(XmlPullParser parser, String namespace, String name, 
            PropertyInfo expected) throws IOException, XmlPullParserException {

        return String.valueOf(parser.nextText());
    }


    public void register(SoapSerializationEnvelope cm) {
         cm.addMapping(cm.xsd, "string", String.class, this);

    }


    public void writeInstance(XmlSerializer writer, Object obj) throws IOException {
           writer.text(obj.toString());
        }

}

我在 onCreate() 中调用这个 callWebService() 方法，如下所示：

callWebService(ID , (float)location.getLongitude() , (float)location.getLatitude());

然后，当我运行我的应用程序时，它会从 gps 获得修复，但在发送数据时执行 Web 服务它给了我：

java.lang.RuntimeException: Cannot serialize...

有人可以向我解释我应该添加什么以使其正常工作吗？我真的不知道，在尝试使用元帅类的线索之后......

4

1 回答 1

2

尝试使用 SOAP Envelope 发送数据，SOAP Envelope 的语法：

final String envelope = "<?xml version=\"1.0\" encoding=\"utf-8\"?>"+
                      "<SOAP-ENV:Envelope SOAP-ENV:encodingStyle=\"http://schemas.xmlsoap.org/soap/encoding/\" " +
                      "xmlns:SOAP-ENV=\"http://schemas.xmlsoap.org/soap/envelope/\" " +
                      "xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" " +
                      "xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\"" +
                      " xmlns:SOAP-ENC=\"http://schemas.xmlsoap.org/soap/encoding/\" " +
                      "xmlns:tns=\"urn:registerwsdl\">"+
                      "<SOAP-ENV:Body>"+
                      "<tns:register " +
                      "xmlns:tns=\"urn:registerwsdl\">"+
    "<your_feild_name xsi:type=\"xsd:string\">"+"your_value"+"</your_feild_name>"+



                      "</tns:register>"+

                               // "</SOAP-ENV:Body></SOAP-ENV:Envelope>",Name,Email,Password,Status,Type,Date];
                               "</SOAP-ENV:Body></SOAP-ENV:Envelope>";

然后在这个函数中使用这个信封，你可以用肥皂信封传递多个值

String CallWebService(String url,
            String soapAction,
           String envelope)  {
          final DefaultHttpClient httpClient=new DefaultHttpClient();
          // request parameters

          HttpParams params = httpClient.getParams();
             HttpConnectionParams.setConnectionTimeout(params, 20000);
             HttpConnectionParams.setSoTimeout(params, 25000);
             // set parameter
          HttpProtocolParams.setUseExpectContinue(httpClient.getParams(), true);

          // POST the envelope
          HttpPost httppost = new HttpPost(url);
          // add headers
             httppost.setHeader("soapaction", soapAction);
             httppost.setHeader("Content-Type", "text/xml; charset=utf-8");

             String responseString="";
             try {

              // the entity holds the request
           HttpEntity entity = new StringEntity(envelope);
           httppost.setEntity(entity);

           // Response handler

           ResponseHandler<String> rh=new ResponseHandler<String>() {
            // invoked when client receives response

               public String handleResponse(HttpResponse response)
              throws ClientProtocolException, IOException {

             // get response entity
             HttpEntity entity = response.getEntity();


             // read the response as byte array
                   StringBuffer out = new StringBuffer();
                   byte[] b = EntityUtils.toByteArray(entity);

                   // write the response byte array to a string buffer
                   out.append(new String(b, 0, b.length));

                   return out.toString();
            }
           };

           responseString=httpClient.execute(httppost, rh); 

          }
             catch (Exception e) {
              Log.v("exception", e.toString());
          }

             xml =  responseString.toString();
             // close the connection
             System.out.println("xml file ------"+xml);
          httpClient.getConnectionManager().shutdown();
          return responseString;
         }

最后使用任何 XML 解析器解析 XML 输出。

于 2012-11-23T04:47:51.233 回答