python - 如何编写一个计算python中总分的函数？

Question

如何在python中编写一个计算总分的函数？

例如，

      rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']]

第一名得5分，第二名得2分，第三名得0分，最后一名得9分。

我想要一个计算人总点数的列表

Answer 1

这对你有用吗？

In [277]: rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']]

In [278]: points = collections.defaultdict(int)

In [279]: for rank_lis in rank_list:
   .....:     for score, person in ran
random     range      rank_list  
   .....:     for score, person in enumerate(rank_lis[::-1]):
   .....:         points[person] += score
   .....:         

In [280]: points.items()
Out[280]: [('Amy', 5), ('John', 3), ('Kitty', 1), ('Peter', 3)]

更有效的解决方案：

In [285]: rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']]

In [286]: for rank_lis in rank_list:
    for score, person in enumerate(rank_lis, -3):
        points[person] -= score
   .....:         

In [287]: points.items()
Out[287]: [('Amy', 5), ('Peter', 3), ('Kitty', 1), ('John', 3)]

Answer 2

你可以使用defaultdict： -

rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']]
my_dict = {0:3, 1:2, 2:1, 3:0}   # Have a mapping from index to score

from collections import defaultdict

ranking = defaultdict(int)

for elem in rank_list:
    for index, value in enumerate(elem):
        ranking[value] += my_dict[index]

print ranking.items()

输出 ： -

[('Amy', 5), ('Kitty', 1), ('Peter', 3), ('John', 3)]

Answer 3

使用反向列表作为索引（因为 0 = 3、3 = 0 等），并保存到字典：

d = {}
for list in rank_list:
  for name in list:
    if name in d:
      d[name] = d[name] + list[::-1].index(name)
    else:
      d[name] = list[::-1].index(name)

list[::-1]反向输出列表。此外，您还可以通过打印获得分数d['Peter']，例如。

Answer 4

它看起来像是collections.Counter的工作：

from collections import Counter

rank_list=[['Peter','Amy','John','Kitty'],['Amy','John','Kitty','Peter']]
rank_by_place = (3, 2, 1, 0)

ranks = Counter()
for record in rank_list:
    for name, rank in zip(record, rank_by_place):
        ranks.update({name: rank})

print ranks.most_common()  # ordered by rank