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我使用休眠作为持久层，这是我的代码示例，但这里是我的 hql 查询：

Query q = s.createQuery("from Login where name=:user and passw =:passw");
  q.setParameter("user",username);
  q.setParameter("passw", passw);
Query q = s.createSQLQuery("SELECT * from Good where Good.supplier =:supl AND Good.name =:gname AND Good.dates >=:sdate and Good.dates <=:fdate").addEntity(Good.class);
   q.setParameter("supl",sup);
   q.setParameter("gname", gname);
   q.setParameter("sdate", sdate);
   q.setParameter("fdate",fdate);

sdate 和 fdate 参数是字符串，在这种情况下可以吗？它抛出这个异常：

com.mysql.jdbc.exceptions.jdbc4.MySQLSyntaxErrorException: You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '.login login0_ where login0_.name='Tom'' at line 1

登录.hbm.xml

<hibernate-mapping>
<class name="kz.bimash.FoodSec.model.Login" table="login" catalog="foodsec">
    <id name="id" type="java.lang.Integer">
        <column name="Id" />
        <generator class="increment" />
    </id>
    <property name="name" type="string">
        <column name="name" length="50" not-null="true" unique="true" />
    </property>
    <property name="passw" type="string">
        <column name="passw" length="50" not-null="true" />
    </property>
    <property name="type" type="string">
        <column name="type" length="45" not-null="true" />
    </property>
    <property name="userId" type="int">
        <column name="userId" not-null="true" />
    </property>
</class>

登录 pojo 类

public class Login  implements java.io.Serializable {


 private Integer id;
 private String name;
 private String passw;
 private String type;
 private int userId;

public Login() {
}

public Login(String username, String password, String type, int userId) {
   this.name = username;
   this.passw = password;
   this.type = type;
   this.userId = userId;
}

public Integer getId() {
    return this.id;
}

public void setId(Integer id) {
    this.id = id;
}
public String getName() {
    return this.name;
}

public void setName(String username) {
    this.name = username;
}
public String getPassw() {
    return this.passw;
}

public void setPassw(String password) {
    this.passw = password;
}
public String getType() {
    return this.type;
}

public void setType(String type) {
    this.type = type;
}
public int getUserId() {
    return this.userId;
}

public void setUserId(int userId) {
    this.userId = userId;
}

登录DAO类 

@Repository
public class LoginDAO {
@Autowired
private SessionFactory sf;
@SuppressWarnings("empty-statement")
public String[] Authorise(String username, String passw){
  Session s = sf.getCurrentSession();
  s.beginTransaction();
  Query q = s.createQuery("from Login where name=:user and passw =:passw");
  q.setParameter("user",username);
  q.setParameter("passw", passw);
  q.setMaxResults(1);
  String[] str = null;
  Login login = null;
  for(Iterator it = q.iterate(); it.hasNext();){
   login = (Login)it.next();

  }
  if(login != null){
      str = new String[]{login.getType(), String.valueOf(login.getUserId())};

  }
        s.getTransaction().commit();
    return str;
}
public boolean checkLogin(String username){
    Session s = sf.getCurrentSession();
    s.beginTransaction();
   // String s_sql ="SELECT * FROM Login WHERE NAME="+username;
    Query q = s.createQuery("from Login where name = :usern");
    q.setParameter("usern", username);
   // Query q=s.createSQLQuery(s_sql);
    List<Login> logins =null;
    logins= (List<Login>)q.list();
    s.getTransaction().commit();
    if(logins !=null)
        return true;
    else
        return false;
}

}

4

1 回答 1

1

以下代码段存在问题：

Query q = s.createSQLQuery("SELECT * from Good where Good.supplier =:supl AND Good.name =:gname AND Good.dates >=:sdate and Good.dates <=:fdate").addEntity(Good.class);

您正在编写 SQL 而不是 HQL。这就是为什么你使用session.createSQLQuery(...)而不是session.createQuery(...). createSQLQuery(...)始终返回 的引用org.hibernate.SQLQuery，而您已将其分配给 的变量Query。

我很惊讶为什么您没有收到编译时错误。

尝试将其分配给SQLQuery变量并检查它是否有效。

于 2012-11-22T10:28:09.747 回答