这是我第一次尝试在 Java Web 应用程序中使用 j_security 检查表单身份验证。我正在使用 Eclipse 3.6 和 Apache Tomcat 6.0.28。
问题描述:当我使用有效凭据提交登录表单时,j_security check 会将我重定向到 error.html 中定义的错误页面。当我使用无效凭据提交时,它也会将我带到 error.html 页面。这很好,但对于有效用户,我希望在登录后被带到受保护的资源。
登录.html
<!DOCTYPE html>
<html>
<head>
<meta charset="ISO-8859-1">
<title>Login</title>
</head>
<body>
<form method=post action="j_security_check">
Username <input type="text" name="j_username"><br />
Password <input type="password" name= "j_password"><br />
<input type="submit" value="submit">
</form>
</body>
</html>
web.xml
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee
http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd"
version="2.5">
<servlet>
<servlet-name>Faces Servlet</servlet-name>
<servlet-class>javax.faces.webapp.FacesServlet</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>Faces Servlet</servlet-name>
<url-pattern>*.jsf</url-pattern>
</servlet-mapping>
<context-param>
<param-name>javax.faces.PROJECT_STAGE</param-name>
<param-value>Development</param-value>
</context-param>
<welcome-file-list>
<welcome-file>/ui/index.xhtml</welcome-file>
<welcome-file>index.html</welcome-file>
</welcome-file-list>
<login-config>
<auth-method>FORM</auth-method>
<form-login-config>
<form-login-page>/security/login.html</form-login-page>
<form-error-page>/security/error.html</form-error-page>
</form-login-config>
</login-config>
<security-constraint>
<display-name>URLsConstraintMechanism</display-name>
<web-resource-collection>
<web-resource-name>clientURL</web-resource-name>
<url-pattern>/ui/*</url-pattern>
<http-method>GET</http-method>
<http-method>PUT</http-method>
<http-method>POST</http-method>
<http-method>DELETE</http-method>
</web-resource-collection>
<auth-constraint>
<role-name>tomcat</role-name>
</auth-constraint>
</security-constraint>
<security-role>
<description>The Only Secure Role</description>
<role-name>tomcat</role-name>
</security-role>
</web-app>
tomcat-users.xml
<role rolename="tomcat"/>
<role rolename="role1"/>
<user username="tomcat" password="tomcat" roles="tomcat"/>
<user username="both" password="tomcat" roles="tomcat,role1"/>
<user username="role1" password="tomcat" roles="role1"/>
我在 IDE 的控制台或 $CATALINA_HOME/logs 文件夹中也没有看到任何错误
请原谅任何遗漏,因为我是这个论坛的新手。我已经搜索了现有的线程,但到目前为止没有任何建议对我有用。