我有这个查询。所有的选择在技术上都是相同的,只是乘数的一个递增值。我需要这个高达* 64。
关于如何以比我现在更有效的方式做到这一点的任何建议?
SELECT
CONVERT(INT,cast(reverse(substring(char_data, 305+16*1, 2)) as BINARY(2))) AS inventory1,
CONVERT(INT,cast(reverse(substring(char_data, 305+16*2, 2)) as BINARY(2))) AS inventory2,
CONVERT(INT,cast(reverse(substring(char_data, 305+16*3, 2)) as BINARY(2))) AS inventory3,
CONVERT(INT,cast(reverse(substring(char_data, 305+16*4, 2)) as BINARY(2))) AS inventory4,
CONVERT(INT,cast(reverse(substring(char_data, 305+16*5, 2)) as BINARY(2))) AS inventory5,
CONVERT(INT,cast(reverse(substring(char_data, 305+16*6, 2)) as BINARY(2))) AS inventory6,
CONVERT(INT,cast(reverse(substring(char_data, 305+16*7, 2)) as BINARY(2))) AS inventory7,
CONVERT(INT,cast(reverse(substring(char_data, 305+16*8, 2)) as BINARY(2))) AS inventory8,
CONVERT(INT,cast(reverse(substring(char_data, 305+16*9, 2)) as BINARY(2))) AS inventory9,
CONVERT(INT,cast(reverse(substring(char_data, 305+16*10, 2)) as BINARY(2))) AS inventory10
..........SO ON TO 64.............
FROM CHAR_DATA0
WHERE CHAR_KEY=10
非常感谢你们。
- 编辑 -
我正在使用 MSSQL