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我正在尝试使用库 amchart 我尝试遵循站点的示例，它适用于静态数据我想知道如何使用动态数据（即数据库实例）制作图表？谁可以帮助我 http://www.amcharts.com/javascript-charts/stacked-column/

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2 回答 2

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查看这个库：http
://amcharts-php.sourceforge.net/ 我相信还有更多的库，或者您可以自己编写一个。

于 2012-12-06T08:36:45.983 回答
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在您的 servlet 标头中定义 response.setContentType("application/json");

以 JSON 格式创建数据，例如

StringBuffer sb=new StringBuffer();
            sb.append("[");
            if(rs1.next()){
                sb.append("{");
                sb.append("\"country\": \"CH\",");
                sb.append("\"visits\":\""+rs1.getString(1)+"\",");
                sb.append("\"color\":\""+"#FF0F00"+"\"");
                sb.append("},");
                sb.append("{");
                sb.append("\"country\": \"USA\",");
                sb.append("\"visits\":\""+rs1.getString(2)+"\",");
                sb.append("\"color\":\""+"#FF6600"+"\"");
                sb.append("},");
                sb.append("{");
                sb.append("\"country\": \"UK\",");
                sb.append("\"visits\":\""+rs1.getString(3)+"\",");
                sb.append("\"color\":\""+"#FF9E01"+"\"");
                sb.append("},");
                sb.append("{");
                sb.append("\"country\": \"AU\",");
                sb.append("\"visits\":\""+rs1.getString(4)+"\",");
                sb.append("\"color\":\""+"#FCD202"+"\"");
                sb.append("},");
                sb.append("{");
                sb.append("\"country\": \"DK\",");
                sb.append("\"visits\":\""+rs1.getString(5)+"\",");
                sb.append("\"color\":\""+"#F8FF01"+"\"");
                sb.append("},");
                sb.append("{");
                sb.append("\"country\": \"PK\",");
                sb.append("\"visits\":\""+rs1.getString(6)+"\",");
                sb.append("\"color\":\""+"#B0DE09"+"\"");
                sb.append("},");
                sb.append("{");
                sb.append("\"country\": \"ML\",");
                sb.append("\"visits\":\""+rs1.getString(7)+"\",");
                sb.append("\"color\":\""+"#04D215"+"\"");
                sb.append("},");
                sb.append("{");
                sb.append("\"country\": \"JP\",");
                sb.append("\"visits\":\""+rs1.getString(8)+"\",");
                sb.append("\"color\":\""+"#0D8ECF"+"\"");
                sb.append("},");
                sb.append("{");
                sb.append("\"country\": \"IN\",");
                sb.append("\"visits\":\""+rs1.getString(9)+"\",");
                sb.append("\"color\":\""+"#0D52D1"+"\"");
                sb.append("},");
                sb.append("{");
                sb.append("\"country\": \"TW\",");
                sb.append("\"visits\":\""+rs1.getString(10)+"\",");
                sb.append("\"color\":\""+"#2A0CD0"+"\"");
                sb.append("}");


                }
            sb.append("]");

然后做out.write(sb.toString());

然后在 html 文件中从请求对象中获取数据 var test=JSON.parse(xmlhttp.responseText);

记得我在这个中使用过 Ajax ....

于 2013-02-12T06:02:44.130 回答