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如何将多个参数传递给我通过 pool.map 调用的函数?

我的代码:

import gevent
from gevent.pool import Pool

def process(param1, param2):
    return "dosomething"

pool = Pool(10)
jobs = [('arg1a', 'arg1b'), ('arg2a', 'arg2b')]

# should pass arguments so that it results in these calls
# process(param1=arg1a, param2=arg1b)
# process(param1=arg2a, param2=arg2b)
results = pool.map(process, jobs) # does not work
4

1 回答 1

4

看来该gevent.Pool.map方法只允许将单个项目作为参数传递给您提供的函数。但是,您可以编写函数代码以非常轻松地解压缩其参数:

def process(params):
    param1, param2 = params
    ...

或者,您可以在调用时使用 lambda 表达式处理参数解包pool.map

results = pool.map(lambda args: process(*args), jobs)
于 2012-11-21T09:57:47.917 回答