运行此代码时，游戏永远不会宣布获胜或平局，它会不断要求下一个玩家移动......
示例输出：
Choose a position to play
1 | 2 | 3
---------
4 | 5 | 6
---------
7 | 8 | 9
Player X (Enter a position or -1 to resign): 1
Choose a position to play.
1 | 2 | 3
---------
4 | 5 | 6
---------
7 | 8 | 9
Player O (Enter a position or -1 to resign): 1
它不会改变角色的空格数，甚至不会记住它来宣布获胜者。
这是我的代码的 runStandardGame() 部分，我认为问题出在哪里？
//***RUN STANDARD GAME******************************************************
static void runStandardGame() {
int position = QUIT;
char playerChar = 'X';
boolean isGameOver = false;
fillPosition();
System.out.println("Choose a position to play.\n");
displayGrid();
do {
System.out.print("Player " + playerChar +
" (Enter a position or " + QUIT + " to resign): ");
position = keyboard.nextInt();
System.out.println("Choose a position to play.\n");
displayGrid();
if(isWin()) {
System.out.print("\nPlayer " + playerChar + " WINS!!!\n");
isGameOver = true;
}
else if (isTie()) {
System.out.print("\nTIE.\n");
isGameOver = true;
}
else {
//switch players because one of the players has just played
//and not won;, so, it is the other player's turn
if (playerChar == 'X') {
playerChar = 'O';
}
else{
playerChar = 'X';
}
}
}while(!isGameOver && position != QUIT);
}//end of runStandardGame
甚至可能只是游戏部分，因为那是分配给数组的地方......
//***PLAY*******************************************************************
static void play(int cell, char playerChar) {
//the player has entered a number 1 through 9 for the position they want
//to play, so, figure out which row and which column of the array this is
//For example, if the player wants to play 'X' in position 7, this means
//the 'X' must go into row 2, column 0 of the array
int row = 0;
int column = 0;
if (cell > 0 && cell <= (STANDARD_GRID_ROWS * STANDARD_GRID_COLUMNS)){
row = (cell - 1) / STANDARD_GRID_ROWS;
column = (cell - 1) % STANDARD_GRID_COLUMNS;
grid[row][column] = playerChar;
}
}
任何帮助表示赞赏。谢谢你。