c - 编译稀疏 0.4.1

Question

我正在尝试编译一个依赖 sparse 0.4.1 的项目，但在尝试编译 sparse 0.4.1 时，我最终遇到以下编译器错误：

included from parse.c:25:
./parse.h:63:22: error: member of anonymous struct redeclares 'label_statement'
                        struct statement *label_statement;
                                          ^
./parse.h:40:22: note: previous declaration is here
                        struct statement *label_statement;

这让我很困惑，因为它们是两个不同结构的不同成员，所以为什么抱怨呢？

代码如下所示：

struct statement {
    enum statement_type type;
    struct position pos;
    union {
            struct /* declaration */ {
                    struct symbol_list *declaration;
            };
            struct /* label_arg */ {
                    struct symbol *label;
                    struct statement *label_statement;
            };
            struct {
                    struct expression *expression;
                    struct expression *context;
            };
            struct /* return_statement */ {
                    struct expression *ret_value;
                    struct symbol *ret_target;
            };
            struct /* if_statement */ {
                    struct expression *if_conditional;
                    struct statement *if_true;
                    struct statement *if_false;
            };
            struct /* compound_struct */ {
                    struct statement_list *stmts;
                    struct symbol *ret;
                    struct symbol *inline_fn;
                    struct statement *args;
            };
            struct /* labeled_struct */ {
                    struct symbol *label_identifier;
                    struct statement *label_statement;
            };
.......

Answer 1

你在同一个 union 中声明语句 label_statement 两次，第一次在第 40 行，第二次在第 63 行

     struct statement *label_statement;

尝试编辑第二个的名称。