说我有这样的事情：
class Product(models.Model)
name = models.CharField()
description models.TextField()
class Image(models.Model)
product = models.ForeignKey(Product, null=True, blank=True, related_name="images")
image = models.ImageField()
假设我正在创建一个表单，Product并且在这个表单中有一个部分允许您上传图像。这些图像是异步上传的。我怎样才能拥有它：
创建时：
创建产品并且图像与之相关。
编辑时：
获取产品，获取相关图像。产品已编辑，图像已编辑。
目前，我有一个视图可以同时完成创建或编辑的工作Products。如何完成此产品表单的图像相关部分？模型表单集？
编辑：
@login_required
def create_or_edit_product(request, product_id=None):
# Redirect user if he has no account associated to him
try:
account = Account.objects.get(membership__user=request.user)
except:
login_url = reverse('login') + ('?next=%s') % request.path
return HttpResponseRedirect(login_url)
# Get product if product id passed
product_instance = None
if product_id is not None:
product_instance = get_object_or_404(product, id=product_id)
# Get related pictures if product exists. Get picture values (dictionary list, used for initial formset data) if pictures found.
pictures = product.pictures.all() if product_instance is not None else None
pictures_values = pictures.values() if pictures else []
PictureFormSet = formset_factory(PictureForm, formset=BasePictureFormSet, extra=0, can_delete=False, max_num=40)
if request.method == "POST":
product_form = productForm(request.POST, prefix='product', instance=product_instance)
picture_formset = PictureFormSet(request.POST, prefix='pictures', initial=pictures_values)
# If forms are valid
if product_form.is_valid() and picture_formset.is_valid():
try:
# Add account to product and save
product = product_form.save(commit=False)
if product_instance is None:
product.account = account
product.save()
# Remove picture-product relationships of current pictures
if pictures is not None:
pictures.update(product=None)
# Update each picture with the product and corresponding sort order. (The field 'id' is a picture object. The form converts the passed picture id to a picture object)
for index, form in enumerate(picture_formset):
picture = form.cleaned_data['id']
Picture.objects.filter(id=picture.id).update(product=product, sort_order=index)
except Exception, e:
# Rollback changes - something went wrong
transaction.rollback()
print "Transaction Rollback: %s" % e
else:
# Commit changes and redirect to product edit page
transaction.commit()
return HttpResponseRedirect('product_edit', product_id=product.id)
else:
product_form = productForm(prefix='product', instance=product_instance)
picture_formset = PictureFormSet(prefix='pictures')
# TODO: change add template to an add/edit one
return render_to_response('products/add.html', {
'product_form' : product_form,
'picture_formset' : picture_formset,
'pictures' : pictures,
},
context_instance=RequestContext(request))
我是 Python 和 Django 的新手，但这是我的一些工作观点。（到目前为止，我只尝试添加新产品）
用户看到的表单具有包含每个图片 ID 的隐藏输入的缩略图。如果表单失败，我想重新显示缩略图以及隐藏的输入（已经保留）。为了使它工作，我猜我必须查询图片ID，但表格无效，那么我该怎么做呢？（如果这甚至是正确的道路）
你怎么看？